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eduard
2 years ago
7

A mass attached to a 66.4 cm long string starts from rest and is rotated 36.6 rev in1 min before reaching a final angular speed.

1. Determine the angular acceleration of the mass, assuming that it is constant. Answer in units of rad/s².2. What is the angular speed of the mass after 1 min? Answer in units of rad/s².
Physics
1 answer:
andrey2020 [161]2 years ago
5 0

Answer:

0.128 rad/s², 7.66 rad/s

Explanation:

length, l = 66.4 cm

initial angular speed, ωo = 0 rad/s

Let ω be the final angular speed.

Let α be the angular acceleration.

number of revolution, n = 36.6

time, t = 1 min = 60 second

Angle turned, θ = 2πn = 2 x 3.14 x 36.6 = 229.85 rad

Use second equation of motion for angular motion

\theta =\omega _{0}t+\frac{1}{2}\alpha t^{2}

229.85 = 0 + 0.5 x α x 60 x 60

α = 0.128 rad/s²

Use first equation of motion

ω = ωo + αt

ω = 0 + 0.128 x 60

ω = 7.66 rad/s

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2 years ago
A weather balloon is rising vertically from a launching pad on the ground. A technician standing 300 feet from the launching pad
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\dfrac{dh}{dt} =5\ ft/s

Explanation:

Let

h = height of balloon (in feet).

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\dfrac{dh}{d\theta } = 300 sec^2\theta

now  \dfrac{dh}{dt} can be written as

\dfrac{dh}{dt} =\dfrac{dh}{d\theta }\times \dfrac{d\theta }{dt}

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When θ = π/4,

\dfrac{dh}{d\theta } = 300 sec^2\theta

\dfrac{dh}{d\theta } = 600

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2 years ago
You need to determine the density of an unknown liquid and decide to perform an experiment. You notice that a wooden block float
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Answer:

pu = 1260.9kg/m^3

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The density of a liquid is inversely proportional to the volume (height) of object submerged in it.

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since V = Ah

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p = density

h = height submerged

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the density of the unknown liquid is 1260.9kg/m^3

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2 years ago
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