Answer:
dispersion forces
Explanation:
SO3 is a trigonal planar molecule. All the dipoles of the S-O bonds cancel out making the molecule to be a nonpolar molecule.
The primary intermolecular force in nonpolar molecules is the London dispersion forces. As expected, the London dispersion forces is the intermolecular force present in SO3.
Hence SO3 is a symmetrical molecule having only weak dispersion forces acting between its molecules.
Because its molecules can slide around each other, a liquid<span> has the ability to flow. The resistance to such flow is called the </span>viscosity<span>. For organic liquids, as the chain increases the viscosity increases as well due to the bonding that is present. Therefore, the ranking should be as follows:
</span><span>CH3CH2CH2CH2CH2CH2CH2CH2CH2CH3
</span><span>CH3CH2CH2CH2CH2CH2CH2CH3
</span><span>CH3CH2CH2CH2CH2CH3 </span>
i think it's A. cause CH is 1:1 and if you reduce C2H2, the ratio would also be 1:1
<span>carbon = 42.1%
hydrogen = 6.5%
oxygen = 51.4%
First lookup the molar mass of carbon, hydrogen, and oxygen.
mass of carbon = 12.0107
mass of hydrogen = 1.00794
mass of oxygen = 15.999
Now calculate the molar mass of each element in sucrose multiplying the atomic weight of each element by the number of times the element is used.
carbon = 12 * 12.0107 = 144.1284
hydrogen = 22 * 1.00794 = 22.17468
oxygen = 11 * 15.999 = 175.989
Calculate the molar mass of sucrose by adding the mass of each element used.
144.1284 + 22.17468 + 175.989 = 342.2921
Finally, calculate the percentage by mass of each element by dividing the mass used for each element by the total mass of sucrose.
carbon = 144.1284 / 342.2921 = 0.421068 = 42.1%
hydrogen = 22.17468 / 342.2921 = 0.064783 = 6.5%
oxygen = 175.989 / 342.2921 = 0.514149 = 51.4%</span>
Answer:
Explanation:
Atomic mass of element will be weighted average atomic mass of the element
= 89.90470 x 0 .5293 + 90.90565 x. 1154 + 91.90504 x 0. 1765 + 93.90632 x 0.1788
= 47.58955 + 10.490 + 16.2212 + 16.790
= 91.10 u .
