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Andrews [41]
1 year ago
14

You've just solved a problem and the answer is the mass of an electron, me=9.11×10−31kilograms. How would you enter this number

into the answer box?
Enter your answer in kilograms using three significant figures. Note that the units are provided for you to the right of the answer box.

Physics
2 answers:
scoray [572]1 year ago
7 0

The mass of an electron up to three significant digits is written as \boxed{9.11 \times {{10}^{ - 31}}\,{\text{kg}}}.

Further Explanation:

The significant numbers in a measured quantity are the numbers that have their role in representation of the measured quantity in terms of the resolution of the quantity.

The scientific notation for any measured quantity is expressed as:

A = a... \times {10^n}  

Here, a are the combined significant digits in the quantity.

The number of digits present in a represents the number of significant digits in the representation of the quantity.

The following is the list of rules to be considered for the significant numbers.

a) Each and every non-zero number is a significant number.

b) A zero present between two significant numbers is also a significant number.

c) The zeros written after the decimal point are significant numbers.

d) Only zero before a decimal is not a significant number.

Therefore, the mass of an electron up to three significant digits is written as \boxed{9.11 \times {{10}^{ - 31}}\,{\text{kg}}} and the three significant digits in the number are 9,1\& 1.

Learn More:

  1. which of the following is not a component of a lever brainly.com/question/1073452
  2. forces of attraction limit the motion of particles most in brainly.com/question/947434
  3. the amount of kinetic energy an object has depends on its brainly.com/question/137098

Answer Details:

Grade: High School

Chapter: Significant Figures

Subject: Physics

Keywords: Significant figures, answer box, rules, non-zero, scientific notation, resolution, measured quantity, physical quantity, mass of electron.

mamaluj [8]1 year ago
6 0

The mass of an electron, me, 9.11 × 10⁻³¹ kilograms shows there are 3 important numbers in them, namely numbers 9, 1, and 1

<h3><em>Further explanation</em></h3>

Significant numbers are obtained from measurement results of exact numbers and the last number estimated

This is called significant numbers

the scientific notation can be described as:

a, ... x 10ⁿ

a, ... called a significant number

10ⁿ is called a big order

Rules for significant numbers in general:

  • 1. All non-zero numbers are significant numbers
  • 2. a zero which is located between two non-zero numbers including a significant number
  • 3. all zeros are located in the final row written behind the decimal point of the include significant number
  • 4. zero decimal point is the not significant number

From the numbers known in the question amounting to 9.11 × 10⁻³¹ kilograms shows there are 3 important numbers in them,(symbol a, before a big order ,called a significant number) namely numbers 9, 1, and 1

<h3><em>Learn more</em></h3>

significant figures

brainly.com/question/11151926

significant figures in the following number: 5.67 x 106

brainly.com/question/7539478

the number of significant figures is 0.025

brainly.com/question/10343704

0.080 significant figures

brainly.com/question/1999241

the fewest number of significant figures

brainly.com/question/11464470

Keywords : significant number, the scientific notation, decimal point, a big order

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Answer:

A train takes some time to travel 240 km. If the speed had been 20 km per hour more than the one it was carrying, it would have taken 2 hours less to travel this distance. In what time did he cover the 240 km

Explanation:

Given that,

A train travelled a distance of 240km

Let the initial speed be

S_1 = x km/hr

Let assume the time spent on the first journey is

t_1 = a

Now if he increase the speed to

S_2 = (x + 20) km/hr

Then, he would have take 2hrs less time

Then, time t_2 = a - 2

The common data fore the two journey is the distance

Speed = distance / time

For the first stage

S_1 = d / t_1

d = S_1 × a

d = x × a

240 = x•a

x = 240 / a Equation 1

For stage two

d = S_2 × t_2

d = (x+20) × (a - 2)

240 = (x+20) × (a - 2). Equation 2

Substitute equation 1 into 2

240 = (240/a + 20) × (a -2)

240 = 240 - 480/a + 20a - 40

240 - 240 + 40 = - 480/a + 20a

240 - 240 + 40 = (-480 + 20a²) / a

40 = (-480 + 20a²) / a

40a = -480 + 20a²

20a² - 40a -480 = 0

Divided through by 20

a² - 2a - 24 = 0

a² + 4a - 6a - 24 = 0

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(a-6)(a+4) = 0

(a-6) = 0 or (a+4) = 0

So, a = 6 or a = -4

The time cannot be negative, then, the time is a = 6hours

So, t_1 = a = 6hours,

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Spanish

Un tren recorrió una distancia de 240 km.

Deje que la velocidad inicial sea

S_1 = x km / h

Supongamos que el tiempo dedicado al primer viaje es

t_1 = a

Ahora si aumenta la velocidad a

S_2 = (x + 20) km / h

Entonces, habría tomado 2 horas menos de tiempo

Entonces, el tiempo t_2 = a - 2

Los datos comunes para los dos viajes son la distancia.

Velocidad = distancia / tiempo

Para la primera etapa

S_1 = d / t_1

d = S_1 × a

d = x × a

240 = x • a

x = 240 / a Ecuación 1

Para la etapa dos

d = S_2 × t_2

d = (x + 20) × (a - 2)

240 = (x + 20) × (a - 2). Ecuación 2

Sustituye la ecuación 1 en 2

240 = (240 / a + 20) × (a -2)

240 = 240 - 480 / a + 20a - 40

240 - 240 + 40 = - 480 / a + 20a

240 - 240 + 40 = (-480 + 20a²) / a

40 = (-480 + 20a²) / a

40a = -480 + 20a²

20a² - 40a -480 = 0

Dividido entre 20

a² - 2a - 24 = 0

a² + 4a - 6a - 24 = 0

a (a + 4) -6 (a + 4) = 0

(a-6) (a + 4) = 0

(a-6) = 0 o (a + 4) = 0

Entonces, a = 6 o a = -4

El tiempo no puede ser negativo, entonces, el tiempo es a = 6 horas

Entonces, t_1 = a = 6 horas,

Entonces, el tiempo utilizado en el primer viaje es de 6 horas

Entonces, en el segundo viaje, el uso del tiempo es 2 horas menos que el primer viaje

Entonces, t_2 = 6 - 2 = 4 horas

t_1 = 6 horas

t_2 = 4 horas

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Explanation:

Given;

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Area of the small piston, A₁ = πr₁² = π(2.185 cm)² = 15 cm²

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