Answer: They are all true
a. The tension in the rope is everywhere the same.
b. The magnitudes of the forces exerted on the two objects by the rope are the same.
c. The forces exerted on the two objects by the rope must be in opposite directions.
d. The forces exerted on the two objects by the rope must be in the direction of the rope.
Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)
- Cutiepatutie ☺❀❤
Weight = (mass) x (gravity)
Acceleration of gravity on Earth = 9.8 m/s²
Weight on Earth = (mass) x (9.8 m/s²)
Divide each side by (9.8 m/s²): Mass = (weight) / (9.8 m/s²)
Mass = (650 N) / (9.8 m/s²)
Mass = 66.33 kg (rounded)
The number of significant digits of any measurement is determined by the instrument used for such measurement. For example, in this case, we have the height of a small child being measured. We can use a simple ruler for this, and we see that a ruler has ten divisions for 1 cm. This means that the ruler cannot measure beyond the size of 0.1 cm or 1 mm. Hence, when we report the height of the small child, we report it to one significant digit after the decimal place. As an example, if we measure a child's height to be 90 full cm divisions and 8 smaller divisions, we report it as 90.8 cm but not 90.83 or 90.86 cm.
Answer:
From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases
Explanation:
I cannot find any attached photo, but we can proceed anyways theoretically.
The electric field strength (E) at any point in an electric field is the force experienced by a unit positive charge (Q) at that point
i.e
But the force F
But the electric field intensity due to a point charge Q at a distance r meters away is given by
<em>From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases</em>
Answer:
Explanation:
We can use the following SUVAT equation to solve the problem:
where
v = 0 is the final velocity of the car
u = 24 m/s is the initial velocity
a is the acceleration
d = 196 m is the displacement of the car before coming to a stop
Solving the equation for a, we find the acceleration:
