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Answer:
strength of hypericin in mixture = 0.42 %
Explanation:
given data
each lot = 100 g
active component hypericin = 0.3%, 0.7%, and 0.25%
solution
we get here percent strength o hypericin in the mixture that is
Hypericin contribution lot 1 = × 100
Hypericin contribution lot 1 = 0.3 g
and
Hypericin contribution lot 2 = × 100
Hypericin contribution lot 2 = 0.7 g
and
Hypericin contribution lot 3 = × 100
Hypericin contribution lot 3 = 0.25 g
so
total 300 g mixture of hypericin contain = 0.3 g + 0.7 g + 0.25 g
total 300 g mixture of hypericin = 1.25 g
so here percent strength o hypericin in mixture is
strength of hypericin in mixture = × 100
strength of hypericin in mixture = 0.42 %