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vekshin1
2 years ago
3

A square boat with a mass of 544 g is placed in a tank of corn syrup. The corn syrup has a density of 1.36 g/mL. The boat has a

base that measures 8 cm by 8 cm. How far will the boat sink into the corn syrup?
Physics
1 answer:
hammer [34]2 years ago
7 0

Answer:

6.25 cm

Explanation:

Density is defined as mass per unit volume of a substance hence expressed as

d=m/v

Where m is mass of a substance and v is the volume while d represent density.

Making v the subject of formula then

V=m/d

Substituting 544 g for m and 1.36 g/mL for d then

V=544/1.36=400ml

Since 1ml=1cm³ then also 400 ml equals to 400cm³

Volume is given by lwh

V=lwh where l is length, w is width and h is height

Making h the subject of formula

h=V/lw

Substituting 400cm³ for v, 8cm for l and 8cm for w then

h=400/(8*8)=6.25cm

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C.25.50% Hope this helps.
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Mary takes 6.0 seconds to run up a flight of stairs that is 102 meters long. if mary's weight is 87 newtons, what power has mary
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A 3-cm high object is in front of a thin lens. The object distance is 4 cm and the image distance is –8 cm. (a) What is the foca
xenn [34]

Answer:

a) Focal length of the lens is 8 cm which is a convex lens

b) 6 cm

c) The lens is a convex lens and produces a virtual image which is upright and two times larger than the object.

Explanation:

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v = Image distance = -8 cm

f = Focal length

Lens Equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{4}+\frac{1}{-8}\\\Rightarrow \frac{1}{f}=\frac{1}{8}\\\Rightarrow f=\frac{8}{1}=-8\ cm

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Magnification

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c) The lens is a convex lens and produces a virtual image which is upright and two times larger than the object.

8 0
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Find an expression for the torsional constant k in terms of the moment of inertia I of the disk and the angular frequency ω of s
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Answer:

Explanation:

The general equation for the disk with moment of inertia I when given small angular displacement  \theta is given by

I\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=-k\theta

\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}+\frac{k\theta }{I}=0

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k=I\omega ^2

5 0
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