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stiks02 [169]
2 years ago
6

El piloto de un contenedor parte de la ciudad de Guatemala a las 8:00 AM hacia Puerto Barrios, Izabal, debiendo recorrer 310 km

sobre la carretera hasta llegar a la entrada del puerto donde debe entregar el contenedor a las 12:00 del mediodía. Calcule la rapidez promedio a la que deberá conducir el piloto para poderlo entregar a tiempo. Si el piloto sabe de antemano que debe detenerse una hora para hacer cola en el Progreso, por la ampliación de la carretera, calcule cuál debería ser entonces la rapidez promedio a la que debe conducir. ¿Medite si será posible o razonable que un contenedor viaje por la carretera a esa rapidez? Si la distancia en línea recta desde la ciudad de Guatemala hasta Puerto Barrios es de 250 km. ¿Cuál es la longitud de la trayectoria del contenedor? ¿Cuál fue su desplazamiento?
Physics
1 answer:
Keith_Richards [23]2 years ago
6 0
Sorry I don’t understand so I can’t help
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As shown in the figure below, Justin walks from the house to his truck on a windy day. He walks 20 m toward
juin [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The velocity is   v =0.333 \  m/s in positive x -direction

The speed is s = 0.733 \ m/s

Explanation:

From the question we are told that

The distance from the house to truck is  D =  20 m

  The distance traveled back to retrieve  wind-blown hat is  d =  15

  The distance from the wind-blown hat position too the truck is  k =  20  m

  The total time taken is  t  =  75 s

Generally when calculating the displacement the Justin's backward movement to collect his wind - blown hat is taken as negative

Generally Justin's displacement is mathematically represented as

      L  =  20 - 15 + 20

=>    L  =  25 \ m

Generally the average velocity is mathematically represented as

          v  =  \frac{L}{t}

=>      v = \frac{25}{75}

=>      v =0.333 \  m/s

Generally the distance covered by Justin is mathematically represented as  

         R =  D+ d + k

=>      R =  20 + 15 +20

=>     R =  55 \  m

Generally Justin's average speed over a 75 s period is mathematically represented as

            s = \frac{R}{ t}

=>         s = \frac{55}{ 75}

=>        s = 0.733 \ m/s

8 0
2 years ago
(a) Two point charges totaling 8.00 μC exert a repulsive force of 0.150 N on one another when separated by 0.500 m. What is the
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Imagine two people standing at placemark A and placemark E, looking at each other across the fault. Which of the following state
lord [1]

Answer:

To both observers, the land opposite them is moving to the right.

Explanation:

I have this class too. and there is also a quizlet with all the answers to the rest of the other questions. Trust me its right .

https://quizlet.com/261219090/oce-1001-chapter-2-flash-cards/

5 0
2 years ago
Calcular la resistencia de una varilla de grafito de 170 cm de longitud y 60 mm2. Resistividad grafito 3,5 10-5 Ωm
ozzi

Answer:

R = 0.992 Ω

Explanation:

En esta pregunta, dada la información que contiene, debemos calcular la resistencia de la varilla de grafito.

Matemáticamente,

Resistencia = (resistividad * longitud) / Área De la pregunta;

Resistividad = 3,5 * 10 ^ -5 Ωm

longitud = 170 cm = 1,7 m

Área = 60 mm ^ 2 = 60/1000000 = 6 * 10 ^ -5 m ^ 2

Conectando estos valores a la ecuación anterior, tenemos;

Resistencia = (3.5 * 10 ^ -5 * 1.7) / (6 * 10 ^ -5) =

(3.5 * 1.7) / 6 = 0.992 Ω

3 0
2 years ago
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