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Sergeu [11.5K]
2 years ago
9

The mass of Mars is 6.42 × 1023 kg. Its moon Phobos is 9378 kilometers away from Mars and has a mass of 1.06 × 1016 kg. What is

the gravitational force between Mars and Phobos? 5.16 × 1015 N 5.16 × 1021 N 4.84 × 1022 N 4.84 × 1025 N
Physics
2 answers:
dangina [55]2 years ago
4 0

Answer:

5.16 × 1021 N

Hope this helps!

egoroff_w [7]2 years ago
3 0

Answer:

A on Edge 5.16 x 10^15 N

Explanation:

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The power rating of an electric lawn mower is 2000 watts if lawnmower is used for 120 seconds how many joules of work van it do
Scorpion4ik [409]
1 watt = 1 joule/sec

2,000 watts = 2,000 joules/sec

                     (2,000 joule/sec) x (120 sec)

                  = (2,000 x 120)  (joule-sec/sec)

                  =   240,000 joules .
        
4 0
2 years ago
Which changes in an electric motor will make the motor stronger? Check all that apply. using a stronger permanent magnet using a
miv72 [106K]
Use stronger magnets
increase current
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4 0
2 years ago
Read 2 more answers
A typical adult human has a mass of about 70 kg.
Misha Larkins [42]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
a. <span>FM GmMmr2
</span>= 6.67 x 10-11N.m2kg27 .35 x 1022 kg 70 kg 3.78 x 108 m2 
<span>= 2.40 x 10-3 N

b. </span><span>FE GmEmr2
= 6.67 x 10-11 N.m2kg 25 .97 x 1034 kg (70kg) 6.38 x 106 m2
=685 N 
FMFE 2.40 x 10-3N685 N= 0.0004%</span>
3 0
2 years ago
A ray of yellow light ( f = 5.09 × 1014 hz) travels at a speed of 2.04 × 108 meters per second in
SashulF [63]
Velocity = fλ

where f is frequency in Hz, and λ is wavelength in meters.

<span>2.04 * 10⁸ m/s =  5.09 * 10¹⁴  Hz   *  λ </span>

<span>(2.04 * 10⁸ m/s) / (5.09 * 10¹⁴  Hz ) = λ </span>

<span>4.007*10⁻⁷  m =  λ </span>

<span>The wavelength of the yellow light = 4.007*10⁻⁷  m<span> </span></span>
6 0
2 years ago
An 8.0 m, 240 N uniform ladder rests against a smooth wall. The coefficient of static friction between the ladder and the ground
sweet [91]

Answer:

5.7 m

Explanation:

AD = length of the ladder = L = 8 m

AB = distance of the center of mass of the ladder = (0.5) L = (0.5) 8 = 4 m

AC = distance of person on the ladder from the bottom end = x

W = weight of the ladder = 240 N

F_{g} = weight of the person = 710 N

F = force by the wall on the ladder

N = normal force by ground on the ladder = ?

Using equilibrium of force along the vertical direction

N = F_{g} + W

N = 710 + 240

N = 950 N

μ = Coefficient of static friction = 0.55

f =static frictional force on the ladder

Static frictional force is given as

f = μ N

f = (0.55) (950)

f = 522.5 N

Force equation along the horizontal direction is given as

F = f

F = 522.5 N

using equilibrium of torque about point A

F Sin50 (AD) = W Cos50 (AB) + (F_{g} Cos50 (AC))

(522.5) Sin50 (8) = (240) Cos50 (4) + (710) Cos50 (x)

x = 5.7 m

7 0
2 years ago
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