Answer:
Thus, when the volume of the gas is exposed to a temperature above -273.15 K, the volume increases linearly with the temperature.
Explanation:
The expression for Charles's Law is shown below:

This states that the volume of the gas is directly proportional to the absolute temperature keeping the pressure conditions and the moles of the gas constant.
<u>Thus, when the volume of the gas is exposed to a temperature above -273.15 K, the volume increases linearly with the temperature. </u>
<u>For example , if the temperature of the gas is reduced to half, the volume also reduced to half. </u>
<u>At -273.15 K, according to Charles's law, it is possible to make the volume of an ideal gas = 0.</u>
Binding energy is the energy needed to emit the electron from the shell. Using the formula below to compute for BE. Binding Energy BE = Energy of photon - Kinetic energy electron
where
Energy proton= 633 keV
KE electron = 606 keV
Binding energy BE = 27 keVThe binding energy of the k subshell is equal to 27 keV.
The basis of finding the answer to this problem is to know the electronic configuration of Fluorine. That would be: <span>[He] 2s</span>²<span> 2p</span>⁵. The valence electrons, which are the outermost electrons of the atom, are the ones that participate in bonding. <em>Since the highest orbital for F is 2p, that means the highest energy occupied would be 2.</em>
Answer:
<em>3.27·10²³ atoms of O</em>
Explanation:
To figure out the amount of oxygen atoms in this sample, we must first evaluate the sample.
The chemical formula for sodium sulfate is <em>Na₂SO₄, </em>and its molar mass is approximately 142.05
.
We will use stoichiometry to convert from our mass of <em>Na₂SO₄ </em>to moles of <em>Na₂SO₄</em>, and then from moles of <em>Na₂SO₄ </em>to moles of <em>O </em>using the mole ratio; then finally, we will convert from moles of <em>O </em>to atoms of <em>O </em>using Avogadro's constant.
19.3g <em>Na₂SO₄</em> ·
·
·
After doing the math for this dimensional analysis, you should get a quantity of approximately <em>3.27·10²³ atoms of O</em>.