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1 year ago

Calculate the number of atoms in 2.5 mol manganese.

Chemistry

1 answer:

Leokris [45]1 year ago

6 0

Answer:

1.5 × 10²⁴ atoms Mn

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

2.5 mol Mn

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

$2.5 \ mol \ Mn(\frac{6.022 \cdot 10^{23} \ atoms \ Mn}{1 \ mol \ Mn} )$ = 1.5055 × 10²⁴ atoms Mn

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

1.5055 × 10²⁴ atoms Mn ≈ 1.5 × 10²⁴ atoms Mn

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Answer:

(a) A strong acid

Explanation:

We have given the pH of the solution is 2.46

pH=2.46

So the concentration of $H^+=10^{-pH}=10^{-2.46}=0.00346$

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2 years ago

A gas cylinder filled with nitrogen at standard temperature and pressure has a mass of 37.289 g. The same container filled with

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Answer:

Molar mass = 3.9236 g/mol ≅ 4 g/mol

This corresponds to Helium gas.

Explanation:

Let the moles of nitrogen gas = x moles

Moles of carbon dioxide = x moles ( As both are filled at same temperature and pressure conditions )

Given:

$Mass_{Container}+Mass_{Nitrogen\ gas}=37.289\ g$

Molar mass of nitrogen gas, $N_2$ = 28.014 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$x\ moles= \frac{Mass}{28.014\ g/mol}$

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Similarly,

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Molar mass of nitrogen gas, $CO_2$ = 44.01 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$x\ moles= \frac{Mass{44.01\ g/mol}$

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Solving the two equations, we get :

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$moles = \frac{Mass\ taken}{Molar\ mass}$

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$0.00943\ moles= \frac{0.037\ g}Molar mass}$

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2 years ago

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