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geniusboy [140]
2 years ago
15

1. Three confused sled dogs are trying to pull a sled across the Alaskan snow. Tim pulls east with a force of 42 N; Sam also pul

ls east, but with a force of 53 N; and big Ethan pulls west with a force of 67 N. What is the net force on the sled? then find the acceleration?
2. A 944-kg dragster, starting from rest, attains a speed of 31,2 m/s in 0.670 s. a. Find the average acceleration of the dragster.

b. What is the magnitude of the average net force on the dragster during this time?

c. What horizontal force does the seat exert on the driver if the driver has a mass of 68.0 kg?

Please try to atleast answer one
Physics
1 answer:
Bumek [7]2 years ago
6 0

Answer:

Explanation:

According to the statement, three confused sleigh dogs are trying to pull a sled across the Alaskan snow.  

Forces in same direction gets added , so 35N + 42N=77N  and the Net Force is 77N -53N as it is acting in opposite direction.

Net force is 25N in east to the maximum without any hassle.

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thankyou : )

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cluponka [151]

Explanation:

Radius of the circular path, r = 1.25 m

Angular velocity of the ball, \omega=3\ rev/s=18.84\ rad/s

It is placed 1.5 meters above the ground. Using the conservation of energy to find the height of the ball.

mgh=\dfrac{1}{2}mv^2

h=\dfrac{v^2}{2g}

Since, v=r\times \omega

h=\dfrac{(r\omega)^2}{2g}

h=\dfrac{(1.25\times 18.84)^2}{2\times 9.8}

h = 28.29 meter

So, the ball will rise to a maximum height of 1.5 m + 28.29 m = 29.796 meters. Hence, this is the required solution.

4 0
2 years ago
How many neutrons are contained in 2 kg? Mass of one neutron is 1.67x10-27 kg.
liraira [26]

Answer:

1.2 × 10^27 neutrons

Explanation:

If one neutron = 1.67 × 10^-27 kg

then in 2kg...the number of neutrons

; 2 ÷ 1.67 × 10^-27

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4 0
2 years ago
A child is playing with a spring toy, first stretching and then compressing it.
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a bus is moving at 22m/s [E] for 12s. Then the bus driver slows down at 1.2m/s2 [W] until the bus stops. Determine the total dis
KatRina [158]
The total displacement is equal to the total distance. For the east or E direction, the distance is determined using the equation:

d = vt = (22 m/s)(12 s) = 264 m

For the west or W direction, we use the equations:
a = (v - v₀)/t
d = v₀t + 0.5at²

Because the object slows down, the acceleration is negative. So,
-1.2 m/s² = (0 m/s - 22 m/s)/t
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7 0
2 years ago
During the 440, a runner changes his speed as he comes out of the curve onto the home stretch from 18 ft/sec to 38 ft/sec over a
Sloan [31]

Answer:

6.67ft/s^2

Explanation:

We are given that

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Hence, the average acceleration=6.67ft/s^2

5 0
2 years ago
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