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2 years ago

A car impacting another car head-on will have ____________ the force of impact.

2 answers:

8 0

The force of impact would most likely be considered as doubled when a car is impacting another car on a head-on collision. The situation is in accordance to the law of conservation of momentum wherein "the momentum that is present in a system is always constant unless an external force is applied to it."

olya-2409 [2.1K]2 years ago

5 0

Newtons third law says that every action has an equal and opposite reaction, which means that when two cars collide frontally, first car acts on the second car with the same magnitude of the force but with an opposite direction than the second car acts on the first car. So the correct answer is: A car impacting another car head-on will have EQUAL MAGNITUDE BUT THE OPPOSITE DIRECTION OF the force of impact.

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How many times could Haley fly bewteen the two flowers in 1 minute (60 seconds)

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Your low-flow showerhead is delivering water at 1.2×10−4m3/s, about 2.0 gallons per minute.

Oksanka [162]

To solve this problem it is necessary to apply the fluid mechanics equations related to continuity, for which the proportion of the input flow is equal to the output flow, in other words:

$Q_1 = Q_2$

We know that the flow rate is equivalent to the velocity of the fluid in its area, that is,

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A = Cross-sectional Area

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$V_1 = \frac{1.2*10^{-4}}{A_2}$

$V_1 = \frac{1.2*10^{-4}}{\pi r^2}$

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2 years ago

A hiker caught in a rainstorm absorbs 1.00 L of water in her clothing. If it is windy so that the water evaporates quickly at 20

masya89 [10]

Answer:

(A) Q = 2.26×10⁶J

(B) ΔT = 9°C

(C)

Explanation:

We have been given the mass of the hiker, the volume of water from which we can calculate the mass knowing that the density if water is 1000kg/m³.

Evaporation is a phase change and occurs at a constant temperature. We would use the latent heat of vaporization to calculate the amount of heat evaporated.

We would then equate this to the heat change it brings about in the hiker's body and then calculate the temperature drop.

See the attachment below for full solution.

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2 years ago

At the normal boiling temperature of iron, TB = 3330 K, the rate of change of the vapor pressure of liquid iron with temperature

Margaret [11]

The molar latent enthalpy of boiling of iron at 3330 K is ΔH = 342 $\times$ 10^3 J.

<u>Explanation:</u>

Molar enthalpy of fusion is the amount of energy needed to change one mole of a substance from the solid phase to the liquid phase at constant temperature and pressure.

d ln p = (ΔH / RT^2) dt

(1/p) dp = (ΔH / RT^2) dt

dp / dt = p (ΔH / RT^2) = 3.72 $\times$ 10^-3

(p) (ΔH) / (8.31) (3330)^2 = 3.72 $\times$ 10^-3

ΔH = 342 $\times$ 10^3 J.

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2 years ago

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