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jenyasd209 [6]
2 years ago
9

What is the concentration of k+ ions in a 0.045 m k2co3 solution assuming complete dissociation?express the concentration in mol

arity?
Chemistry
2 answers:
laila [671]2 years ago
7 0

<u>Answer:</u> The concentration of K^+ ions in the solution is 0.09 M

<u>Explanation:</u>

We are given:

Concentration of K_2CO_3 = 0.045 M

The chemical equation for complete dissociation of potassium carbonate follows:

K_2CO_3(aq.)\rightarrow 2K^+(aq.)+CO_3^{2-}(aq.)

By stoichiometry of the reaction:

1 mole of potassium carbonate produces 2 moles of potassium ions and 1 mole of carbonate ions.

So, the concentration of potassium ions in the given solution = (2\times 0.045M)=0.09M

Hence, the concentration of K^+ ions in the solution is 0.09 M

kykrilka [37]2 years ago
6 0
<span>(0.045) x (2 K{+} ions / 1 molecule K2CO3) = 0.090 in whatever units the original concentration was expressed in</span>
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