A helium-filled balloon is launched when the temperature at ground level is 27.8°c and the barometer reads 752 mmhg. if the ball
1 answer:
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For q3 to be in equilibrium the total force acting on it has to be zero.
Let's say that total distance traveled by car is L (this is just for the convenience).
We can set up a system of equations to find an answer. Let's say that from q1 to q3 the distance is r_1 and from q3 to q2 the distance is r_2, we know that this distance has to be equal to:
The second equation is going to the total force acting on the charge q3:
k_c is the Coulomb's constant. Since left-hand side is zero we just divide whole equation with k_c to get rid of it:
Let's solve this for r_1^2:
Now we have a quadratic equation with following parameter:
We know that two solutions are:
We need a positive solution. When we plug in all the numbers we get:
Let's say that total distance traveled by car is L (this is just for the convenience).
We can set up a system of equations to find an answer. Let's say that from q1 to q3 the distance is r_1 and from q3 to q2 the distance is r_2, we know that this distance has to be equal to:
The second equation is going to the total force acting on the charge q3:
k_c is the Coulomb's constant. Since left-hand side is zero we just divide whole equation with k_c to get rid of it:
Let's solve this for r_1^2:
Now we have a quadratic equation with following parameter:
We know that two solutions are:
We need a positive solution. When we plug in all the numbers we get:
Answer:
see explanation below
Explanation:
Given that,
500°C
= 25°C
d = 0.2m
L = 10mm = 0.01m
U₀ = 2m/s
Calculate average temperature
262.5 + 273
= 535.5K
From properties of air table A-4 corresponding to = 535.5K
k = 43.9 × 10⁻³W/m.k
v = 47.57 × 10⁻⁶ m²/s
A)
Number for the first strips is equal to
Calculating heat transfer coefficient from the first strip
The rate of convection heat transfer from the first strip is
The rate of convection heat transfer from the fifth trip is equal to
Calculating
The rate of convection heat transfer from the tenth strip is
Calculating
Calculating the rate of convection heat transfer from the tenth strip
The rate of convection heat transfer from 25th strip is equal to
Calculating
Calculating
Calculating the rate of convection heat transfer from the tenth strip
molecular weights are written in the picture.
CH4<NH3<H2O<Cl2
Answer : The rate of heat transfer to the water is, 37.92 kJ/min
Explanation : Given,
Time = 10 min
Mass of water = 200 g
Latent heat of fusion of water = 334 J/g
Latent heat of vaporization of water = 2230 J/g
Now we have to calculate the rate of heat transfer to the water.
Now put all the given values in the above formula, we get:
Thus, the rate of heat transfer to the water is, 37.92 kJ/min