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devlian [24]
2 years ago
3

In the simulation, were you able to use noninteger numbers (like ½ or 0.43) for the coefficients in a balanced equation? Why do

you think this is?
Chemistry
2 answers:
BARSIC [14]2 years ago
4 0
Because half the time the number are either fractions or decimals.
GalinKa [24]2 years ago
4 0

Answer:

By standard convention, decimals and fractions are avoided or rather do away with when balancing chemical equations.

We do not have decimals when balancing equations, because we are balancing atoms and molecules. You can't cut an atom or a molecule in half after all, so you must use whole numbers.

By doing away with decimals and fractions, mole relationships between reactants and products are simply presented.

It is much more understandable and presentable to say; "2 moles of Hydrogen gas reacts with 1 mole of oxygen gas to form2moles of water molecule"

Rather than; "1 moles of Hydrogen gas reacts with 1/2 mole of oxygen gas to form 1 moles of water molecule"

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A redox reaction employed in an electrochemical cell has a negative . Which statement is true? a) E∘cell is positive b) K>1 E
krok68 [10]

Answer:

d. K<1 E∘cell is negative

Explanation:

Since E⁰ = negative , ΔG = -nFE⁰ = -nF -ve = +ve.

Also, ΔG = -RTlnK

K = exp(-RTΔG)

Since ΔG = +ve, -RTΔG = -ve

K = 1/exp(RTΔG) < 1.

So our answer is  E⁰ cell is negative and K < 1

5 0
2 years ago
If a dozen apples has a mass of 2.0 kg and 0.20 bushel is 1 dozen apples, How many bushels of apples are in 1.0 Kg of apples
Maslowich

If 1 dozen apples has a mass of 2.0 kg and 0.20 bushel is 1 dozen apples, how many bushels of apples are in 1.0 kg of apples?

0.1 bushels

7 0
2 years ago
What will be the charge of the ion formed from each of these atoms ?
Galina-37 [17]

Answer:

Si14- Si^4+

As33- As^3-

Mg12- Mg^2+

Rb37- Rb^+

F9- F^-

Ge32- Ge^4+

Sn50- Sn^2+, Sn^4+

Explanation:

The elements shown in the answer have their common ions written beside them.

Silicon mostly forms positive ions in oxyacids and complex ions. Arsenic mostly forms its anion. Magnesium forms only the +2cation just as rubidium only forms the +1 cation. The fluoride ion is F^- while tin may for a +2*or +4 cation. Germanium usually forms the +4 cation.

4 0
2 years ago
Write a half-reaction for the oxidation of the manganese in MnCO3(s) to MnO2(s) in neutral groundwater where the carbonate-conta
Leokris [45]

Answer:MnCO3+2H2O----->MnO2+ HCO3-+2e-+3H+

Explanation:The equation to be balanced is

MnCO3 ------> MnO2+HCO3-

The oxidation number of Mn changes from +2 in MnCO3 to +4 in MnO2

Therefore two electrons must be added to the right as shown below:

MnCO3 -------> MnO2+ HCO3-+ 2e-Now,there is one negative charge HCO3- and 1 negative charge on the two electrons making a total of -3 charges on the right. There is zero charge on the left.

To balance the equation,add3H+on the right,to cancel out the charges.

MnCO3 --------> MnO2+HCO3-+2e-+3H+

Adding H2O to balance Hydrogen and Oxygen atoms:

MnCO3+2H2O ------->MnO2+HCO3-+2e-+3H+

3 0
2 years ago
A large cylindrical tank contains 0.750 m3 of nitrogen gas at 27°C and 7.50 * 103 Pa (absolute pressure). The tank has a tight‐f
Nuetrik [128]

Answer: The answer is 68142.4 Pa

Explanation:

Given that the initial properties of the cylindrical tank are :

Volume V1= 0.750m3

Temperature T1= 27C

Pressure P1 =7.5*10^3 Pa= 7500Pa

Final properties of the tank after decrease in volume and increase in temperature :

Volume V2 =0.480m3

Temperature T2 = 157C

Pressure P2 =?

Applying the gas law equation (Charles and Boyle's laws combined)

P1V1/T1 = P2V2/T2

(7500 * 0.750)/27 =( P2 * 0.480)/157

P2 =(7500 * 0.750* 157) / (0.480 *27)

P2 = 883125/12.96

P2 = 68142.4Pa

Therefore the pressure of the cylindrical tank after decrease in volume and increase in temperature is 68142.4Pa

8 0
2 years ago
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