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adoni [48]
2 years ago
15

A 25.0 g marble sliding to the right at 20.0 cm/s overtakes and collides elastically with a 10.0 g marble moving in the same dir

ection at 15.0 cm/s. after the collision, the 10.0 g marble moves to the right at 22.1 cm/s. find the velocity of the 25.0 g marble after the collision.
Physics
1 answer:
ikadub [295]2 years ago
6 0
In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,

   KE1  = KE2

The kinetic energy of the system before the collision is solved below.

  KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
  KE1 = 6125 g cm²/s²

This value should also be equal to KE2, which can be calculated using the conditions after the collision.

KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)

The value of x from the equation is 17.16 cm/s.

Hence, the answer is 17.16 cm/s. 
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Two parallel plates are a distance apart with a potential difference between them. a point charge moves from the negatively char
Ghella [55]

Answer:

We can relate the kinetic energy of the particle to the potential difference between the plates by following equations:

Work energy theorem:

W_{total} = \Delta K = K_2 - K_1 = w - 0

W = Fx\\F = W/d = w/d

F = Eq \\E = F/q = w/(dq)

V = Ed = \frac{w}{dq} d = w/q

So,

w = Vq

If the distance is doubled and the potential difference is halved, then

w = qV/2

Explanation:

As can be seen from the relationship between kinetic energy and the potential difference, the distance between the plates has no effect on the relation between kinetic energy and the potential difference. Since the charge of the second particle is equal to that of the first one, the new kinetic energy would be half of the first kinetic energy.

3 0
2 years ago
The wavelength of the sound is 0.750m. What is the frequency?
kifflom [539]

wavelength = speed/frequency


 ==> freq. = speed/wavelength = 342.5/0.75 = 456.67 Hz.

6 0
2 years ago
A helicopter is traveling at 86.0 km/h at an angle of 35° to the ground. What is the value of Ax? Round your answer to the neare
jasenka [17]
Answer: 70.5 km/h

Justification:

The question is not clearly stated but it seems you are asking for the x - component of the velocity of the helicopter.

You can find the x and y - components of the velocity using the trigonometric ratios sine and cosine.

The sine ratio relates the y-component and the velocity by:

sin(angle) = y-component of velocity / velocity

The cosine ratio related the x-component and the velocity by:

cos(angle) = x-component of velocity / velocity.

Since you have the angle and the velocity and are asked by the x-component of the velocity, you need to use the cosine ratio:

cos(35°)= x-component / 86.0 km/h

 => x -component = 86.0 km/h * cos(35°) = 70.5 km/h
6 0
2 years ago
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It can be calculated using Boyle's Law.  A.
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irina [24]
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This is the first stanza of the song:

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