Answer:

Explanation:
It is given that,
Mass of the puck, m = 4.8 kg
Initial velocity of the puck, 
After 8 seconds, final velocity of the puck, 
Let the x and y component of force is given by
.
x component of force is given by :


y component of force is given by :


So, the component of the force is
. Hence, this is the required solution.
Answer:
the correct answer is c v₁> 12.5 m / s
Explanation:
This is a one-dimensional kinematics exercise, let's start by finding the link to get up to speed.
v² = v₀² + 2 a₁ x
as part of rest v₀ = 0
a₁ = v² / 2x
a₁ = 25² / (2 120)
a₁ = 2.6 m / s²
now we can find the velocity for the distance x₂ = 60 m
v₁² = 0 + 2 a1 x₂
v₁ = Ra (2 2,6 60)
v₁ = 17.7 m / s
these the speed at 60 m
we see that the correct answer is c v₁> 12.5 m / s
Answer:reactant,active site,enzyme below,substrate,products
Explanation:
It would be "W<span>armer temperatures on earth's surface decrease the evaporation of water."</span>
Answer:
Vp = 1 [m/s]
Explanation:
In order to solve this problem, we must use the principle of conservation of the amount of movement. In the same way, analyze the before and after of the actions.
<u>The moment before</u>
The 50kg person is still hold (no movement) with the 2kg helmet
<u>The moment after</u>
The helmet moves at 25[m/s] in one direction, the person moves in the opposite direction, due to the launch of the helmet.
In this way we can apply the principle of conservation of movement, expressing the before and after. To the left we have the before and to the right of the equal sign we have the after.
Σm*V1 = Σm*V
where:
m = total mass = (2 + 50) = 52[kg]
V1 = velocity before the lunch = 0
(50 + 2)*V1 = (25*2) - (Vp*50)
0 = 50 - 50*Vp
50 = 50*Vp
Vp = 1 [m/s]