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dalvyx [7]
2 years ago
10

A puppy weighing 3 kilograms races through the dog park. if she slows from a speed of 2 meters/second to 1 meter/second, what wi

ll happen to her kinetic energy? use the kinetic energy equation.
a.her kinetic energy decreases to 1.5 j
b.her kinetic energy increases to 1.5 j
c.her kinetic energy remains unchanged
d.her kinetic energy decreases to 1 j.
Physics
2 answers:
Ne4ueva [31]2 years ago
6 0
Your answer is A. If velocity decreases, your kinetic energy would also decrease.
sdas [7]2 years ago
5 0

Answer:The correct answer is option (a).

Explanation:

Mass of the puppy,m = 3 kg

Kinetic energy of the puppy when it was running with speed of 2 m/s:

K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 3kg\times (2 m/s)^2=6 Joules

Kinetic energy of the puppy when it was running with speed of 1 m/s:

K.E'=\frac{1}{2}mv^2=\frac{1}{2}\times 3kg\times (1 m/s)^2=1.5 Joules

When the puppy was running at the speed f 1 m/s her kinetic energy reduced to 1.5 Joules.

Hence, correct answer is option (a).

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2 years ago
A long plastic rod of 20-mm diameter (k = 0.3 W/m · K and rhocp = 1040 kJ/m3 · K) is uniformly heated in an oven as preparation
Simora [160]

Answer:

The temperature that would satisfy is 286.7°C

Explanation:

Given data:

d = 20 mm = 0.02 m

Le = characteristic length = 0.02/4 = 5x10⁻³m

K = 0.3 W/m K

ρCp = 1040 kJ/m³ K = 1.04x10⁶

t = 3 min = 180 s

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According transient heat analysis:

\frac{T-25}{T_{o}-25 } =e^{-(\frac{h}{L_{e}\rho Cp } )t}

\frac{200-25}{T_{o} -25} =e^{-(\frac{10}{5x10^{-3}*1.04x10^{6}  })*180 } \\T_{o} =272.38C

200°C is the limiting temperature, the temperature should not be less to 200°C, then, we suppose a temperature of 210°C (10°C), and find the temperature:

\frac{210-25}{T_{o} -25} =e^{-(\frac{10}{5x10^{-3}*1.04x10^{6}  })*180 } \\T_{o} =286.7C

6 0
2 years ago
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Answer:

Force F = 1535.86 N

the force necessary for his wife to hold onto their child during the collision is 1535.86 N

Explanation:

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Impulse time t = 0.14 seconds

Using the impulse momentum equation,

Impulse = change in momentum

Ft = m(∆v)

Force F = m(∆v)/t

∆v = 16.54 m/s

F = 13×16.54/0.14

Force F = 1535.86 N

5 0
2 years ago
A large blue marble of mass 3.5 g is moving to the right with a velocity of 15 cm/s. The large marble hits a small red marble of
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According to the elastic conservation momentum
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Answer:

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Explanation:

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d=vt=(300000000m/s)(14400s)=4320000000000m=4.32\times10^{12}m

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