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Volgvan
2 years ago
14

When a baseball player catches a baseball, the glove "gives" or moves backward. How does this movement affect the change in mome

ntum of the baseball?
A The change in momentum increases because the impact time increases.

B The change in momentum stays the same because the ball still comes to a stop.
Physics
2 answers:
Strike441 [17]2 years ago
4 0

Answer:

The change in momentum increases because the impact time increases.

Explanation:

When a baseball player catches a baseball, the glove "gives" or moves backward. Momentum of a body is equal to the product of mass and velocity. Also, the change of momentum of an object when it is acted by a force is called impulse. It is represented by J. Mathematically, it can be written as :

J=F.\Delta t=m\Delta v

F is applied force

\Delta t is the time taken by an object to change its momentum

The momentum depends on the force and the time of impact. In this case, as the a baseball player catches a baseball, the gloves move in backward direction. By doing so, the ball comes to rest in larger time.

So, the change in momentum increases because the impact time increases.

photoshop1234 [79]2 years ago
3 0

B The change in momentum stays the same because the ball still comes to a stop.
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An experiment is designed to test what color of light will activate a photoelectric cell the best. The photocell is set in a cir
Natalija [7]

A photoelectric cell is an electronic device which is used to convert light energy into electric energy.The operation of this device is based on photoelectric effect.

Light of suitable frequency i.e greater or equal to threshold frequency will fall on the cathode maintained at negative potential.The electron emission will take place and these electrons are drifted towards the anode which is at positive potential.

Here,only those radiations will be capable of emitting electrons irrespective of surface barrier of metals whose energy is greater than the work function.

We know that the radiation having long wavelength has least energy as energy and wavelength are inversely proportional to each other.

Mathematically\ energy\ E=\frac{hc}{\lambda}

Here h is the Planck's constant,c is the velocity of light.

Here we have been given red light and blue light.

In the visible spectrum of radiation, the red light has longer wavelength than all other colors of light.Hence blue light has more energy as it's wavelength is less as compared to red light.

Hence, the blue light will activate the most and red the least.

3 0
2 years ago
Read 2 more answers
A particle with a charge of -1.24 x 10"° C is moving with instantaneous velocity (4.19 X 104 m/s)î + (-3.85 X 104 m/s)j. What is
astra-53 [7]

Answer:

(a) F= 6.68*10¹¹⁴ N (-k)

(b) F =( 6.68*10¹¹⁴ i  + 7.27*10¹¹⁴ j  ) N

Explanation

To find the magnetic force in terms of a fixed amount of charge q that moves at a constant speed v in a uniform magnetic field B we apply the following formula:

F=q* v X B Formula (1 )

q: charge (C)

v: velocity (m/s)

B: magnetic field (T)

vXB : cross product between the velocity vector and the magnetic field vector

Data

q= -1.24 * 10¹¹⁰ C

v= (4.19 * 10⁴ m/s)î + (-3.85 * 10⁴m/s)j

B  =(1.40 T)i  

B  =(1.40 T)k

Problem development

a) vXB = (4.19 * 10⁴ m/s)î + (-3.85* 10⁴m/s)j X (1.40 T)i =

            = - (-3.85*1.4) k = 5.39* 10⁴ m/s*T (k)

1T= 1 N/ C*m/s

We apply the formula (1)

  F= 1.24 * 10¹¹⁰ C*  5.39* 10⁴ m/s* N/ C*m/s (-k)

   F= 6.68*10¹¹⁴ N (-k)

a)  vXB = (4.19 * 10⁴ m/s)î + (-3.85* 10⁴m/s)j X (1.40 T)k =

             =( - 5.39* 10⁴i - 5.87* 10⁴j)m/s*T

1T= 1 N/ C*m/s

We apply the formula (1)

F= 1.24 * 10¹¹⁰ C*  (  5.39* 10⁴i + 5.87* 10⁴j) m/s* N/ C*m/s

F =( 6.68*10¹¹⁴  i  + 7.27*10¹¹⁴  j  ) N

8 0
2 years ago
8. Find the momentum of a photon in eV/c and in Kg. m/s if the wavelength is (a) 400nm ; (b) 1 Å = 0.1 nm, (c) 3 cm ; and (d) 2
nataly862011 [7]
We use the formula: p = E/c where E = hc / λ. hence, p = h/  λ. where h is the Planck's constant: 6.62607004 × 10-34 m2 kg / s and <span>λ is the wavelenght. 
</span>
a) p = <span>6.62607004 × 10-34 m2 kg / s / 0.1 x10^-9 m = 6.62607 x 10-24 m kg/s
</span>b) p = 6.62607004 × 10-34 m2 kg / s / 3 x10^-2 m = 2.20869 <span>x 10-32 m kg/s
</span>b) p = 6.62607004 × 10-34 m2 kg / s / 2 x10^-9 m = 3.3130 <span>x 10-25 m kg/s</span>
7 0
2 years ago
A stone with mass 0.80 kg is attached to one end of a string 0.90 m long. The string will break if its tension exceeds 60.0 N. T
AleksandrR [38]

Answer:

v=8.2158m/s

Explanation:

(a) Free-body diagram attached.

(b) The stone attached with the string experiences both centripetal (towards the center) and centrifugal (away from the center) forces. The tension of the string counters the centrifugal force until it breaks.

We know that,

Centrifugal force = \frac{mv^2}{r}

where,

m = mass of the stone

v = velocity of the stone

r = length of the string

To find the maximum speed attained by the stone without the string breaking, we must equate:

\frac{mv^2}{r} =60

or, v=\sqrt \frac{{r\times 60}}{m} } =\sqrt{\frac{0.90\times60}{0.80} } =8.2158m/s

5 0
2 years ago
Suppose you look out the window of a skyscraper and see someone throw a tomato downward from above your window. your window is a
photoshop1234 [79]
Formula for height 
<span> r(t) = a/2 t² + v₀ t + r₀
</span><span> where 
</span><span> a = acceleration = -32 ft/sec² (gravity) 
</span><span> v₀ = initial velocity 
</span><span> r₀ = initial height 
</span><span> r(t) = -16t² + v₀ t + r₀
</span> <span>Tomato passes window (height = 450 ft) after 2 seconds: 
</span><span> r(2) = 450
</span><span> -16(4) + v₀ (2) + r₀ = 450 
</span><span> r₀ = 450 + 64 - 2v₀ 
</span><span> r₀ = 514 - 2v₀ 
</span><span> Tomato hits the ground (height = 0 ft) after 5 seconds: 
</span><span> r(5) = 0 
</span><span> -16(25) + v₀ (5) + r₀ = 0
</span> r<span>₀ = 16(25) - 5v₀ 
</span><span> r₀ = 400 - 5v₀ 
</span><span> 
 r₀ = 514 - 2v₀ and r₀ = 400 - 5v₀
</span> <span>514 - 2v₀ = 400 - 5v₀
</span><span> 5v₀ - 2v₀ = 400 - 514
</span> <span>3v₀ = −114 
</span><span> v₀ = −38 
</span><span> Initial velocity = −38 ft/sec (so tomato was thrown down) 
</span><span> (initial height = 590 ft) </span>
4 0
2 years ago
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