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allsm [11]
2 years ago
6

A student needs to use the metric system while measuring the length of a box. Which units should he use?

Physics
2 answers:
Andrews [41]2 years ago
8 0
It depends on the size of the box.

-- If it's one of the boxes printed on a sheet of graph paper,
then he should report the measurement in millimeters.

-- If it's the box that his new smartphone arrived in, then
he should probably use centimeters.

-- If it's the box that the new tractor was shipped to his
grandfather's farm in, then meters is the best unit.
Elden [556K]2 years ago
6 0

Answer:

centimeters

Explanation:

I took the test :)

hope this helps! have a good day! :))

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as your roller coaster climbs to the top of the steepest hill on its track when does the first car have the greatest potential e
pochemuha
...the potential energy that you build while going up the hill on the roller coaster could be let go as kinetic energy -- the energy of motion that takes you down the hill of the roller coaster.
4 0
2 years ago
The average mass of an automobile in the United States is about 1.440x10^6 g express this mass in kilograms
-BARSIC- [3]
From the problem statement, this is a conversion problem. We are asked to convert from units of grams to units of kilograms. To do this, we need a conversion factor which would relate the different units involved. We either multiply or divide this certain value to the original measurement depending on what is asked. From literature, we will find that 1000 grams is equal to 1 kilogram. We use this as follows:

<span> 1.440x10^6 g ( 1 kg / 1000 g ) = 1440 kg</span><span>
</span>
8 0
2 years ago
Given the indices of refraction n1 and n2 of material 1 and material 2, respectively, rank these scenarios on the basis of the p
lisov135 [29]

Answer:

c>d>f=a>b>e

Explanation:

When a pair of medial has greater difference between the their individual refractive indices with respect to vacuum then it has a greater deviation between the refracted ray and the incident ray.

According to the Snell's law:

\rm refractive\ index\ (n)=\frac{speed\ of\ light\ in\ the\ incident\ medium}{speed\ of\ light\ in\ the\ refracted\ medium}

a)

n_1-n_2=1.33-1.00\\=0.33

b)

n_2-n_1=1.46-1.33

=0.23

c)

n_2-n_1=2.42-1.33\\=1.09

d)

n_2-n_1=1.46-1.00\\=0.46

e)

n_1-n_2=1.50-1.33\\=0.17

f)

n_2-n_1=1.33-1.00\\=0.33

c>d>f=a>b>e

5 0
2 years ago
A baseball player exerts a force of 100 N on a ball for a distance of 0.5 mas he throws it. If the ball has a mass of 0.15 kg, w
Aloiza [94]

Answer:

25.82 m/s

Explanation:

We are given;

Force exerted by baseball player; F = 100 N

Distance covered by ball; d = 0.5 m

Mass of ball; m = 0.15 kg

Now, to get the velocity at which the ball leaves his hand, we will equate the work done to the kinetic energy.

We should note that work done is a measure of the energy exerted by the baseball player.

Thus;

F × d = ½mv²

100 × 0.5 = ½ × 0.15 × v²

v² = (2 × 100 × 0.5)/0.15

v² = 666.67

v = √666.67

v = 25.82 m/s

4 0
1 year ago
A wire of 1mm diameter and 1m long fixed at one end is stretched by 0.01mm when a lend of 10 kg is attached to its free end.calc
Otrada [13]

Answer:

E = 1.25×10¹³ N/m²

Explanation:

Young's modulus is defined as:

E = stress / strain

E = (F / A) / (dL / L)

E = (F L) / (A dL)

Given:

F = 10 kg × 9.8 m/s² = 98 N

L = 1 m

dL = 10⁻⁵ m

A = π/4 (0.001 m)² = 7.85×10⁻⁷ m²

Solve:

E = (98 N × 1 m) / (7.85×10⁻⁷ m² × 10⁻⁵ m)

E = 1.25×10¹³ N/m²

Round as needed.

5 0
2 years ago
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