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Georgia [21]
2 years ago
7

A dilute solution of co2 in water contains 0.000540 g of co2 per 500.0 g of solution. What is the concentration of co2 in ppb?

Chemistry
1 answer:
Ksenya-84 [330]2 years ago
6 0
<h3>Answer:</h3>

                  1080 ppb

<h3>Explanation:</h3>

                            Parts Per Billion is defined as the number of parts of a solute per one billion parts of a solution.

                  ppb  =  (Weight of Solute / Weight of Solution) × 10⁹

Data Given;

                 Weight of Solute (CO₂)  =  0.000540 g

                 Weight of Solution  =  500 g

Putting Values,

                 ppb  =  (0.000540 g / 500 g) × 10⁹

                 ppb  =  1.08 × 10⁻⁶ × 10⁹

                 ppb  =  1080 

<h3>Result:</h3>

          It means if given solution is containing 1 billion particles then 1080 particles in that are of CO₂.

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Answer:

Maintaining a high starting-material concentration can render this reaction favorable.

Explanation:

A reaction is <em>favorable</em> when <em>ΔG < 0</em> (<em>exergonic</em>). ΔG depends on the temperature and on the reaction of reactants and products as established in the following expression:

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To make ΔG < 0 when ΔG° > 0 we need to make the term R.T.lnQ < 0. Since T is always positive we need lnQ to be negative, what happens when Q < 1. Q < 1 implies the concentration of reactants being greater than the concentration of products, that is, maintaining a high starting-material concentration will make Q < 1.

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2 years ago
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8 0
2 years ago
You have a 16.0-oz. (473-mL) glass of lemonade with a concentration of 2.66 M. The lemonade sits out on your counter for a coupl
salantis [7]

<u>Answer:</u> The new concentration of lemonade is 3.90 M

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}     .....(1)

Molarity of lemonade solution = 2.66 M

Volume of solution = 473 mL

Putting values in equation 1, we get:

2.66M=\frac{\text{Moles of lemonade}\times 1000}{473}\\\\\text{Moles of lemonade}=\frac{2.66\times 473}{1000}=1.26mol

Now, calculating the new concentration of lemonade by using equation 1:

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Putting values in equation 1, we get:

\text{New concentration of lemonade}=\frac{1.26\times 1000}{323}\\\\\text{New concentration of lemonade}=3.90M

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2 years ago
When 200g of AgNO3 solution mixes with 150 g of NaI solution, 2.93 g of AgI precipitates, and the temperature of the solution ri
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Answer:

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Explanation:

Hello,

In this case, we can compute the change in the solution enthalpy by using the following formula:

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Whereas the mass of the solution is 350 g, the specific heat capacity is 4.184 J/g °C and the change in the temperature is 1.34 °C, therefore, we obtain:

\Delta H=350g*4.184\frac{J}{g\°C} *1.34\°C\\\\\Delta H=1962.3J

It is important to notice that the mass is just 350 g that is the reacting amount and by means of the law of the conservation of mass, the total mass will remain constant, for that reason we compute the change in the enthalpy as shown above, which is positive due to the temperature raise.

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Answer: i need help

Explanation:

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