answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ahrayia [7]
2 years ago
11

1. What volume of toluene do you need to add to 1 mL of ethyl acetate to make an equi-molar mixture? The density of ethyl acetat

e (C4H8O2) is 0.898 g/mL and the density of toluene (C7H8) is 0.867 g/mL.
Chemistry
1 answer:
galben [10]2 years ago
4 0

Answer:

1.06 mL of toluene will be needed.

Explanation:

Equi-molar mixture means equal moles of all the components.

as given the volume of ethyl acetate = 1mL

Density of ethyl acetate = 0.898 g/mL

The relation between density, mass and volume is :

density=\frac{mass}{volume}

mass=volumeXdensity

mass of ethyl acetate present = 1mL X 0.898g/mL = 0.598 grams

the moles are related to mass as:

moles=\frac{mass}{molarmass}

For ethyl acetate molar mass = 4X12+8X1+2X16= 88g/mol

moles of ethyl acetate will be:

moles=\frac{0.898}{88}= 0.01mol

So we need 0.01 moles of toluene also

For 0.01 moles the mass of toluene required = 0.01 X molar mass of toluene

mass required = 0.01 X 92=0.92grams

for 0.92 grams of toluene volume required will be:

volume=\frac{mass}{density}=\frac{0.92}{0.867}= 1.06mL

You might be interested in
Calculate the number of grams of solute in 500.0 mL of 0.189 M KOH.
KIM [24]

Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

Solution : Given,

Volume of solution = 500 ml

Molarity of KOH solution = 0.189 M

Molar mass of KOH = 56 g/mole

Formula used :

Molarity=\frac{\text{Mass of KOH}\times 1000}{\text{Molar mass of KOH}\times \text{Volume of solution in ml}}

Now put all the given values in this formula, we get the mass of solute KOH.

0.189M=\frac{\text{Mass of KOH}\times 1000}{(56g/mole)\times (500ml)}

\text{Mass of KOH}=5.292g

Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

7 0
1 year ago
Read 2 more answers
COCl2(g) decomposes according to the equation above. When pure COCl2(g) is injected into a rigid, previously evacuated flask at
mestny [16]

<u>Answer:</u> The value of K_p for the reaction at 690 K is 0.05

<u>Explanation:</u>

We are given:

Initial pressure of COCl_2 = 1.0 atm

Total pressure at equilibrium = 1.2 atm

The chemical equation for the decomposition of phosgene follows:

                  COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)

Initial:            1                    -         -

At eqllm:       1-x                 x        x

We are given:

Total pressure at equilibrium = [(1 - x) + x+ x]

So, the equation becomes:

[(1 - x) + x+ x]=1.2\\\\x=0.2atm

The expression for K_p for above equation follows:

K_p=\frac{p_{CO}\times p_{Cl_2}}{p_{COCl_2}}

p_{CO}=0.2atm\\p_{Cl_2}=0.2atm\\p_{COCl_2}=(1-0.2)=0.8atm

Putting values in above equation, we get:

K_p=\frac{0.2\times 0.2}{0.8}\\\\K_p=0.05

Hence, the value of K_p for the reaction at 690 K is 0.05

3 0
1 year ago
Which two solutions, when mixed together, will undergo a double replacement reaction and form a white, solid substance
Scrat [10]

Which two solutions, when mixed together, will undergo a double replacement reaction and form a white, solid substance?


1. NaCl(aq) and LiNO3(aq)

2. KCl(aq) and AgNO3(aq)  answer

3. KCl(aq) and LiCL(aq)

4. NaNO3(aq) and AgNO3(aq)


2 is the answer because AgCl is formed and that is a white ppt.

5 0
2 years ago
Read 2 more answers
What would the % p, on the npk ratio, be reported as for a 100g sample containing 7.5g of phosphorous?
kati45 [8]
When the concentration is expressed in percentage, you simply have to divide the amount of substance to the total amount of the mixture, then multiply it by 100. In this case, when you want to find the percentage of P in the sample, the solution is as follows:

%P = 7.5 g/100 g * 100 =<em> 7.5%</em>
6 0
2 years ago
Read 2 more answers
In which of the compounds below is there more than one kind of hybridization (sp, sp2, sp3) for carbon? I. CH 3CH 2CH 2CH 3 II.
77julia77 [94]

The compounds containing more than one kind of hybridization (sp, sp2, sp3) for carbon is CH3CH = CHCH3.

<u>Explanation</u>:

  • Orbital hybridization is the idea of blending nuclear orbitals into new hybrid orbitals reasonable for the matching of electrons to form chemical bonds in the valence bond hypothesis.  

Here CH3CH = CHCH3 contains a carbon atom joined to more than 3 hydrogen atoms.  

  • In sp – Hybridisation 1 s-orbital and 1 p-orbital are blended to form two sp – hybrid orbitals, having a straight structure.  In sp2 – Hybridisation   1 s-orbital and 2 p-orbitals are blended forming three sp2–hybrid orbitals, having a planar triangular structure.  In  sp3 – Hybridisation  1 s-orbital and 3 p-orbitals are blended forming four sp3–hybrid orbitals having a tetrahedral structure.
8 0
2 years ago
Other questions:
  • If a 0.10 M solution of a colored substance has a maximum absorbance at 500 nm and an absorbance of 0.26 M at this wavelength, w
    14·1 answer
  • Material A has a small latent heat of fusion. Material B has a large heat of fusion. Which of the following statements is true?
    7·2 answers
  • According to the following reaction, how many grams of chloric acid (HClO3) are produced in the complete reaction of 31.6 grams
    10·1 answer
  • (a) What are the possible values of l for n = 4? (Enter your answers as a comma-separated list.)
    15·1 answer
  • Tag all the carbon atoms with pi bonds in this molecule. If there are none, please check the box.
    6·1 answer
  • Roundup, an herbicide manufactured by Monsanto, has the formula C3H8NO5P. How many moles of molecules are there in a 669.1-g sam
    12·1 answer
  • A few drops of a mixture of sodium hydroxide(NaOH) solution and copper (II) tetraoxosulphate (VI) solution were added to a sampl
    15·1 answer
  • A mixture containing 20 mole % butane, 35 mole % pentane and rest
    15·2 answers
  • Which MOST CLOSELY identifies a theme in this passage?
    8·1 answer
  • The nucleoside adenosine exists in a protonated form with a pKa of 3.8. The percentage of the protonated form at pH 4.8 is close
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!