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muminat
2 years ago
13

When balancing an assembly line, which of the following is not a way to reduce the longest task time below the required workstat

ion cycle time? A. Upgrade the equipment B. Assign a roaming helper to support the line C. Split the task between two workstations D. Speed up the assembly line transfer mechanism E. Use a more skilled worker.
Physics
1 answer:
tiny-mole [99]2 years ago
6 0

Answer:

D. Speed up the assembly line transfer mechanism

Explanation:

All of the options are logic and very intelligent ways to reduce the longest task time, but if you just speed up the assembly line transfer you will end up with two possible outcomes, frustrated workers cause they always have to be rushing up to finish their task and thus a lower quality in the product you are producing, or that the workers on that specific part of the assembly line definetely can´t perform the task and endu up not doing their job and you end up with incomplete products.

You might be interested in
We can learn a lot about the properties of a star by studying its spectrum. All of the followingstatements are true except one.
Kisachek [45]

Answer:

B. The total amount of light in the spectrum tells us the star’s radius.

Explanation:

A.

The effective temperature of a star can be determined by means of its spectrum¹ and Wien's displacement law.                    

Since stars behave in a local way as a blackbody, it will take the wavelength at which is the peak of emission greater in the continuum (see the image below).

Then, the maximum peak of emission (\lambda_{max}) will be replaced in the next equation of the Wien's displacement law:

T = \frac{2.898x10^{-3} m. K}{\lambda max}  (1)

Where T is the effective temperature of the star.

Bodies that are hot enough emits light as consequence of its temperature. For example, a iron bar in contact with fire will start to change colors as the temperature increase, until it gets to a blue color, which its know as Wien's displacement law. Which establishes that the peak of emission for the spectrum will be displaced to shorter wavelengths as the temperature increase.

The same scenario described above can be found in the stars, a star whit higher temperature will have a blue color and one with lower temperature, a red color.

B.

Since star does not have the same size, they have different brightness, That is because the photons have a free mean path greater in a bigger radius.

So a star brightness is a consequence of its radius.

               

C.  

Spectral lines will be shifted to the blue part of the spectrum1 if the source of the observed light is moving toward the observer, or to the red part of the spectrum when it is moving away from the observer (that is known as the Doppler effect).        

By using that shift in the spectral lines, the Doppler velocity can be determined.

v = c\frac{\Delta \lambda}{\lambda_{0}}  (2)

Where \Delta \lambda is the wavelength shift, \lambda_{0} is the wavelength at rest, v is the velocity of the source and c is the speed of light.

   

D.

When a photon is absorbed by an electron in an atom of a particular element in the star photosphere, the electron will be pass to a higher state, when it comes back to the ground state, a photon will be emitted again. If the emitted photon does not go in the same direction of the incident photon an absorption line will be created in the spectrum of the star.          

This patterns of spectral lines in the spectrum of the star are compared with the patterns that are got by lamps of that element in a laboratory.

Key term:

¹Spectrum: decomposition of light in its characteristic colors (wavelengths).

3 0
2 years ago
On a hypothetical scale X The ice point is 40° and steam point is 120°.
arlik [135]

Answer:

The reading of Y is -10°.

Explanation:

For scale X, the ice point is 40° and steam point is 120°.

Difference between the two extremes for scales X = 120 - 40 = 80

For scale X, the ice point and steam points are -30° and 130° respectively.

Difference between the two extremes for scales X = 130 - (-30) = 160

Comparing both scales:

One unit of scale X = x

One unit of scale Y = y

Scale X has 80 divisions while scale Y has 160

80x = 160y

x = 2y

50° in scale X = 10x + ice point in X scale

10 divisions in Y scale = 20y

Reading of Y scale = ice point of Y + 20y

= -30° + 20°

= -10°

7 0
2 years ago
A horizontal water jet strikes a stationary vertical plate at a rate of 5 kg/s with a velocity of 35 km/hr. Assume that the wate
Nina [5.8K]

Answer:

48.6 N

Explanation:

rate of mass per second, dm/dt = 5 kg/s

Velocity, v = 35 km/hr = 9.72 m/s

Force acting on the plate

F = v x dm/dt

F = 9.72 x 5 = 48.6 N

Thus, the force acting on the plate is 48.6 N.

3 0
2 years ago
If a force always acts perpendicular to an object's direction of motion, that force cannot change the object's kinetic energy.
laiz [17]
This is very good conceptual question and can clear your doubts regarding work-energy theorem.
Whenever force is perpendicular to the direction of the motion, work done by that force is zero.
According to work-energy theorem,
Work done by all the force = change in kinetic energy.

here, work done = 0.
Therefore, 
0=change in kinetic energy
This means kinetic energy remains constant.
Hope this helps
5 0
2 years ago
A shot-putter exerts a force of 0.142 kN on a shot, accelerating it to 22.75 m/s2. What is the mass of the shot?
Svetach [21]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Force and Power.

Since, according to the Newton's law,

Force = mass * Acceleration.

hence, here

Force = 142 N, accelration = 22.75 m/s2

hence, mass = 142/22.75

===> Mass = 6.24 Kg

hence the mass of the shot is 6.24 Kg

8 0
2 years ago
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