I think the correct answer would be the first option. The elements that hydrogen fuel cells need to produce electricity are oxygen and hydrogen. The hydrogen is broken into protons and electrons with the aid of a catalyst which them reacts with oxygen producing water, heat and electricity.
To solve this problem we will apply the concepts related to the centripetal force, for which it is necessary to equate it with the static friction force of the body. From this, we will clear the speed and replace with the given values. Our values are defined as,
Maximum velocity can be find out using centripetal force,
Must be equal to,
Therefore the maximum speed that he can travel through the arc without slipping is 9.93m/s
This is simply defined as the energy of an object as an attribute of a physical movement
Force
This is simply defined as the energy of an object as an attribute of a physical movement
it is important to note that a tripping for will be a force opposing motion therefore
For a 70kg man trip on a force the for it must me acted upon by a Force
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Answer:
a. 30 N / m
b. 9.0 N
Explanation:
Given that
Unstretched length of the spring, 
= 20.0cm = 0.2m
a) When the mass of 4.5N is hanging from the second spring, then extended length Is
= 35.0cm = 0.35m
So, the change in spring length when mass hangs is
= (0.35 - 0.20) m
= 0.15m
As spring are identical
Let us assume that the spring constant be "k", so at equilibrium
Restoring Force on spring = Block weightage
kx = W = 4.50
= 30 N / m
b) Now for the third spring, stretched the length of spring is
= 50cm = 0.5m
So, the change in spring length is
= (0.5-0.20)m
= 0.30m
At equilibrium,
Restoring Force on spring = Block weightage
Now using all mentioned and computed values in above,
= 30(0.3)
= 9.0 N
Okay, here is my stab at this, I hope it helps!
You know the bullet's initial velocity, V₀ = 450 m/s
You know the final velocity, V = 220 m/s
You also know how long the bullet accelerates (actually decelerates), 14cm, or .14 m
With this information, you learn that you need this equation.
V² = V₀² + 2a (x - x₀), because we have all the information except a, which is the acceleration. So putting it into the equation, it looks like this.
(220m/s)² = (450m/s)² +2a(.14m - 0m)
I'll let you solve the rest, but here are some hints. Your answer will be really big because the bullet slows down really quickly in a really small distance, and you answer will be negative, because this acceleration is causing the bullet to go slower, which is also called deceleration. Hope that helps!
