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shutvik [7]
2 years ago
8

The force shown in the attached figure is the net eastward force acting on a ball. The force starts rising at t = 0.012 s, falls

back to zero at t = 0.062 s, and reaches a maximum force of 35 N at the peak. Determine with an error no bigger than 25% (high or low) the magnitude of the impulse (in N-s) delivered to the ball. Hint: Do not use J = FΔt. Look at the figure. Find the area of a nearly equally sized triangle.

Physics
1 answer:
kifflom [539]2 years ago
6 0
Impulse = Integral of F(t) dt from 0.012s to 0.062 s

Given that you do not know the function F(t) you have to make an approximation.

The integral is the area under the curve.

The problem suggest you to approximate the area to a triangle.

In this triangle the base is the time: 0.062 s - 0.012 s = 0.050 s

The height is the peak force: 35 N.

Then, the area is [1/2] (0.05s) (35N) = 0.875 N*s

Answer> 0.875 N*s
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When the mass of the bottle is 0.125 kg, the KE is______ kg m2/s2.
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Answers are:
(1) KE = 1 kg m^2/s^2
(2) KE = 2 kg m^2/s^2
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Explanation:

(1) Given mass = 0.125 kg
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Since Kinetic energy = (1/2)*m*(v^2)

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(2) Given mass = 0.250 kg
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(3) Given mass = 0.375 kg
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Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
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2 years ago
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