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charle [14.2K]
2 years ago
5

A student prepares a solution by combining 100 mL of 0.30 M HNO2(aq) and 100 mL of 0.30 M KNO2(a). Which of the following equati

ons represents the reaction that best helps to explain why adding a few drops of 1.0 M HCI(aą) does not significantly change the pH of the solution? (A) K*(aq) + CI (aq) ---------------->KCl(s)(B) HNO2(aą) ----------------->H'(aą) + NO2 (aq) (C) H (aq) + OH (aq) ----------------->H2O(l)
Chemistry
1 answer:
katrin2010 [14]2 years ago
7 0

Answer:

B

Explanation:

This creates a buffer solution meaning it will just neutralize out and does not change the PH massively.

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During a lab experiment performed at STP conditions, you prepare HCl by reacting 100. ml of Cl2 gas with an excess of H2 gas.
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Answer: 19.4 mL Ba(OH)2

Explanation:

H2(g) + Cl2(g) --> 2HCl(aq) (make sure this equation is balanced first)

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0.100 L Cl2 • (1 mol / 22.4 L) = 0.00446 mol Cl2

Use the mole ratio of 2 mol HCl for every 1 mol Cl2 to find moles of HCl produced.

0.00446 mol Cl2 • (2 mol HCl / 1 mol Cl2) = 0.00892 mol HCl

HCl is a strong acid and Ba(OH)2 is a strong base so both will completely ionize to release H+ and OH- respectively. You need 0.00892 mol OH- to neutralize all of the HCl. Note that one mole of Ba(OH)2 contains 2 moles of OH-.

0.00892 mol OH- • (1 mol Ba(OH)2 / 2 mol OH-) • (1 L Ba(OH)2 / 0.230 M Ba(OH)2) = 0.0194 L = 19.4 mL Ba(OH)2

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