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ra1l [238]
2 years ago
8

A physics student uses a spring loaded launcher to fire a 58 gram projectile horizontally. The projectile leaves the launcher at

6.0 m/s when the spring is compressed by 2.0 cm.
Physics
1 answer:
timofeeve [1]2 years ago
3 0

Answer:

no answer

Explanation:

the question does not sk what to find

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Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. Th
Stels [109]

This question deals with the law of conservation of momentum, which basically says that the total momentum in a system must stay the same, provided there are no outside forces. Since you were given the mass and velocity of the two objects you can find the momentum (p=mv) of each and then add them together to find the total momentum of the system before they collide. This total momentum must be the same after they collide.  Since you have the mass and velocity of one of the objects after the collision you can find the its momentum after.  Subtract this from the the system total and you will have the momentum of the other object after the collision.  Now that you know the momentum of the other object you can find its velocity using p=mv and its mass from before.

Be careful with the velocities.  They are vectors, so direction matters.  Typically moving to the right is positive (+) and moving to the left is negative (-).  It is not clear from your question which direction the objects are moving before and after the collision.

6 0
2 years ago
Read 2 more answers
A swimming pool heater has to be able to raise the temperatureof the 40,000 gallons of water in the pool by 10 degress Celsius.H
andrew11 [14]

Answer:b)1770 kWh

Explanation:

Given

volume of water V=40,000 gallons

Temperature rise \Delta T=10^{\circ}C

c=4186 J/kg-^{\circ} C

also 1 kg mass is approximately is 1 gallon

therefore 40,000 gallon is equivalent to 3.8\times 40000 kg

heat Required to raise temperature is

Q=mc\Delta T

Q=3.8\times 40000\times 4186\times 10

Q=63,627.2\times 10^5 J

Q=63,672.2\times 10^2 KJ

Q=1767.42 kWh\approx 1770 kWh

3 0
2 years ago
Find the impulse of a 50. kg object under the following scenarios:
Alisiya [41]
B. The object stops from a velocity of 12.0 m/s
7 0
2 years ago
A ship 1200m off shore fires a gun. how long after the gun is fired will it be heard on the shore?​
ryzh [129]

Answer:

We know that the speed of sound is 343 m/s in air

we are also given the distance of the boat from the shore

From the provided data, we can easily find the time taken by the sound to reach the shore using the second equation of motion

s = ut + 1/2 at²

since the acceleration of sound is 0:

s = ut + 1/2 (0)t²

s = ut    <em>(here, u is the speed of sound , s is the distance travelled and t is the time taken)</em>

Replacing the variables in the equation with the values we know

1200 = 343 * t

t = 1200 / 343

t = 3.5 seconds (approx)

Therefore, the sound of the gun will be heard at the shore, 3.5 seconds after being fired

6 0
2 years ago
A 68 kg runner exerts a force of 59 N. what is the acceleration of the runner
LuckyWell [14K]
<span>.87 m/s^2 ,hope this helps!!!!!!</span>
8 0
2 years ago
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