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WINSTONCH [101]
2 years ago
14

Which best describes the effect of J. J. Thomson’s discovery?

Chemistry
2 answers:
Svet_ta [14]2 years ago
5 0

Answer is: the accepted model of the atom was changed.

J.J. Thomson placed two oppositely charged electric plates around the cathode ray. He did experiments using different metals as electrode materials and found that the properties of the cathode ray remained constant no matter what cathode material he used.

Tomson concluded that atoms are divisible and that the corpuscles are their building blocks (atoms are made up of smaller particles).  

J. J. Thomson discovered the electron in 1897.  

His "plum pudding" model (1904) suggested: the electrons are embedded in the positive charge.  

With this model, he abandoned his earlier hypothesis (the atom was composed of immaterial vortices).  

sergey [27]2 years ago
3 0

answer is A the accepted model of the atom was changed

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in sample of elemental bromine, 55% or the atoms are Br-79, and the remainder are Br-81. if this sample is typical of naturally
Gwar [14]

Answer:

The average atomic mass of bromine is 79.9 amu.

Explanation:

Given data:

Percentage of Br⁷⁹ = 55%

Percentage of Br⁸¹ = 45%

Average atomic mass of bromine = ?

Formula:

Average atomic mass = [mass of isotope× its abundance] + [mass of isotope× its abundance] +...[ ] / 100

Now we will put the values in formula.

Average atomic mass = [55 × 79] + [81 ×45] / 100

Average atomic mass = 4345 + 3645 / 100

Average atomic mass = 7990 / 100

Average atomic mass = 79.9 amu

The average atomic mass of bromine is 79.9 amu.

3 0
2 years ago
If you find that the hydrogen alpha line in a star’s spectrum occurs at a wavelength of 656.45 nm, what is the star’s approximat
Paladinen [302]

Answer:

The answer to the question is

The star’s approximate radial velocity is 68.52 km/s

Explanation:

To solve the

The formula is

\frac{\lambda-\lambda_{rw}}{\lambda_{rw}} = \frac{v_r}{c} where

v_r = velocity of the star

λ = Star's spectrum wavelength = 656.45 nm

\lambda_{rw} = Rest wavelength = 656.30 nm

c = Speed of light = 299 792 458 m / s

Therefore we have

\frac{656.45-656.30}{656.30} =\frac{v_r}{299 792 458} or v_r = 68518.7699 m/s or 68.52 km/s

8 0
2 years ago
Which of the following reactions are possible if sodium is more reactive than aluminum, 3 iron, and lead?
Deffense [45]

Answer:

Reaction I: Sodium + Aluminum chloride →Sodium chloride + Aluminum

Explanation:

Sodium being more reactive means that it will take the place of aluminium in whats called a displacement reaction and form.

Sodium chloride + Aluminum

8 0
2 years ago
Read 2 more answers
Which of the following gives the molarity of a 17.0% by mass solution of sodium acetate, CH 3COONa (molar mass = 82.0 g/mol) in
weeeeeb [17]

Answer:

The molarity of this solution is 2.26 M (option D)

Explanation:

Step 1: Data given

Mass % = 17%

Molar mass of CH3COONa = 82.0 g/mol

Density of the solution = 1.09 g/mL

Step 2:

Assume the mass of the solution is 1.00 gram

⇒ 17.0 % CH3COONa = 0.17 grams

⇒ 83.0 % H2O = 0.83 grams

Step 3:

Density = 1.09 g/mL

Volume of the solution = total mass / density of solution

Volume of solution : 1.00 grams / 1.09 g/mL

Volume of the solution = 0.917 mL = 0.000917 L

Step 4: Calculate  number of moles of CH3COONa

Number of moles = Mass / molar mass

Number of moles CH3COONa = 0.170 grams / 82.0 g/mol

Number of moles = CH3COONa = 0.00207 moles

Step 5: Calculate molarity

Molarity = moles / volume

Molarity solution =   0.00207 / 0.000917 L

Molarity solution =  2.26 mol/L = 2.26 M

The molarity of this solution is 2.26 M (option D)

6 0
2 years ago
The plant food contains nh4)3po4 what tests would you run to verify the presence of the nh4 ion and the po4 ion
algol13

For the presence of ammonium ion, there is a need to add sodium hydroxide solution to the water and warm the mixture. Test any vapor that gets produced with damp red litmus paper. It should turn blue as ammonia gas is discharged, which is alkaline. The ionic equation for the reaction is:  

NH₄⁺ + OH⁻ ⇒ NH₃ + H₂O

For the presence of phosphate ions, the addition of barium ions is done. The ionic equation is:  

3Ba₂⁺ + 2PO4³⁻ ⇒ Ba₃ (PO₄)₂ (precipitate)


8 0
2 years ago
Read 2 more answers
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