Explanation:
The waveform expression is given by :
...........(1)
Where
y is the position
t is the time in seconds
The general waveform equation is given by :
..........(2)
Where
On comparing equation (1) and (2) we get :
f = 93.10 Hz
Time period,
T = 0.010 s
Phase constant,
Hence, this is the required solution.
To solve this problem we will use the concepts related to angular motion equations. Therefore we will have that the angular acceleration will be equivalent to the change in the angular velocity per unit of time.
Later we will use the relationship between linear velocity, radius and angular velocity to find said angular velocity and use it in the mathematical expression of angular acceleration.
The average angular acceleration
Here
= Angular acceleration
Initial and final angular velocity
There is not initial angular velocity,then
We know that the relation between the tangential velocity with the angular velocity is given by,
Here,
r = Radius
= Angular velocity,
Rearranging to find the angular velocity
Remember that the radius is half te diameter.
Now replacing this expression at the first equation we have,
Therefore teh average angular acceleration of each wheel is
Answer:
16,18,22
Or
1,3,7
Explanation:
The detailed explanation is contained in the image attached. The lengths are found using Pythagoras theorem and the two lengths reflects the two values of x yielded by the quadratic equation
Answer:
a) the values of the angle α is 45.5°
b) the required magnitude of the vertical force, F is 41 lb
Explanation:
Applying the free equilibrium equation along x-direction
from the diagram
we say
∑Fₓ = 0
Pcosα - 425cos30° = 0
525cosα - 368.06 = 0
cosα = 368.06/525
cosα = 0.701
α = cos⁻¹ (0.701)
α = 45.5°
Also Applying the force equation of motion along y-direction
∑Fₓ = ma
Psinα + F + 425sin30° - 600 = (600/32.2)(1.5)
525sin45.5° + F + 212.5 - 600 = 27.95
374.46 + F + 212.5 - 600 = 27.95
F - 13.04 = 27.95
F = 27.95 + 13.04
F = 40.99 ≈ 41 lb
