Answer:
e*P_s = 11 W
Explanation:
Given:
- e*P = 1.0 KW
- r_s = 9.5*r_e
- e is the efficiency of the panels
Find:
What power would the solar cell produce if the spacecraft were in orbit around Saturn
Solution:
- We use the relation between the intensity I and distance of light:
I_1 / I_2 = ( r_2 / r_1 ) ^2
- The intensity of sun light at Saturn's orbit can be expressed as:
I_s = I_e * ( r_e / r_s ) ^2
I_s = ( 1.0 KW / e*a) * ( 1 / 9.5 )^2
I_s = 11 W / e*a
- We know that P = I*a, hence we have:
P_s = I_s*a
P_s = 11 W / e
Hence, e*P_s = 11 W
Answer:
Explanation:
Given that:
mass of object A, 
mass of object B, 
speed of object A, 
So, according to the conservation of momentum, the momentum before collision is equal to the momentum after conservation.
Answer:
a. FTh = 30 N
b. Fw = 30 N
c. a = 200 m/s2
Explanation:
See full explanation in the picture. Please rate as brainliest
Research studies are made because they want to solve problems that are occurring in the society. The benefits of research would eventually benefit the politics, especially because they have the power to implement these solutions to the problems. They don't usually delve into research because it is too technical. It is not their area of expertise. Questions may come up that they can't answer.
Answer:
a) n = 1.33, b) t = 87 10⁻⁹ m
Explanation:
Part A.
The thin anti-reflection film should create destructive interference for the desired wavelength.
2t sin θ = (m + ½) λₙ
The 2 goes out of the path of the beam inside the film, lam is the wavelength modulated by the refractive index of the film
λₙ = λ₀ / n
2t = (m + ½) λ₀ / n
n = (m+ ½) λ₀/2t
Suppose we are in the first inference m = 0
n = (½ 480 10-9)/ 2 90
n = 1.33
Part B
We do not know the refractive index of the glass explicitly, but in general it is of the order of 1.5, so since the index of the film is lower, there is no phase change.
2t = (m + ½) λ₀ / n
t = 1/4 480 10⁻⁹ / 1.38
t = 87 10⁻⁹ m
