Answer:
all these are physical properties except release of heat so it's probably heat energy given off
Answer:
The correct option is: B) H₂0 and OH⁻ as a conjugate pair
Explanation:
According to Brønsted-Lowry theory, the<u> </u><u>acids</u><u> are the chemical substances that form a conjugate base by donating a proton</u> and <u>bases</u><u> are the chemical substances that form conjugate acid by accepting a proton.</u>
In the given chemical reaction: PO₄³⁻(aq) + H₂O(l) ⇄ HPO₄²⁻(aq) + OH⁻(aq)
<u>According to Brønsted-Lowry theory, PO₄³⁻ and OH⁻ are bases. Whereas, H₂O and HPO₄²⁻ are acids.</u>
<u>Also, PO₄³⁻ and HPO₄²⁻ are the conjugate acid-base pair; and H₂O and OH⁻ are the conjugate acid-base pair.</u>
Answer:
The answer to your question is F = 28800 N
Explanation:
Data
q₁ = q₂ = 0.004 C
distance = r = 5 m
k = 9x 10⁹ C
Force = F
Formula
F = k q₁ q₂ / r²
-Substitution
F = (9 x 10⁹)(0.004)(0.004) / (5)²
-Simplification
F = 144000 / 25
-Result
F = 28800 N
-Conclusion
The force of repulsion between these balloons is 28800 N
Remember that the formula to calculare KA is the following
<span>Ka = [H+ ion]*[conj. base] / [acid]
</span>Now that you have the data you can do as the following:
<span>Ka = [H+]*[base] / [acid] </span>
<span>Ka = [x]*[x] / [acid - x] </span>
<span>Ka = x^2 / [acid - x]
</span>then we go
<span>Ka = [.032]^2 / [.220 - .032]
</span>Ka = <span> 5.4 x 10^-3.
Or what is the same
Ka = </span><span>.0054
</span>