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adoni [48]
2 years ago
5

A spacecraft is filled with 0.500 atm of N2 and 0.500 atm of O2. Suppose a micrometeor strikes this spacecraft and puts a very s

mall hole in its side. Under these circumstances,
A. O2 is lost from the craft 6.9% faster than N2 is lost.

B. O2 is lost from the craft 14% faster than N2 is lost.

C. N2 is lost from the craft 6.9% faster than O2 is lost.

D. N2 is lost from the craft 14% faster than O2 is lost.

E. N2 and O2 are lost from the craft at the same rate.
Chemistry
2 answers:
Archy [21]2 years ago
7 0

Answer:

N2 is lost from the craft 6.9% faster than O2 is lost.

Explanation:

<u>Step 1:</u> Data given

0.500 atm of N2

0.500 atm of 02

Molar mass of 02 = 2*16 g/mole = 32 g/mole

Molar mass of N2 = 2* 14 g/mole = 28g/mole

<u>Step 2:</u> Calculate the rate of loss

r1N2 / r2O2 = √(M2(02)/M1(N2))  = √(32/28) = 1.069

1.069-1)*100= 6.9%

This means N2 is lost from the craft 6.9% faster than O2 is lost.

quester [9]2 years ago
5 0

Answer:

C. N₂ is lost from the craft 6.9% faster than O₂ is lost.

Explanation:

The rate of effusion of a gas (r) is inversely proportional to the square root of its molar mass (M), as expressed by the Graham's law.

\frac{rN_{2}}{r_{O_{2}}} =\sqrt{\frac{M(O_{2})}{M(N_{2})} } =\sqrt{\frac{32.00g/mol}{28.00g/mol} } =1.069\\rN_{2}=1.069rO_{2}

The rate of effusion of N₂ is 1.069 times the rate of effusion of O₂, that is, N₂ effuses 6.9% faster than O₂.

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3 0
2 years ago
How much energy is required to melt a 500. gram block of iron? The heat of vaporization is 6090 J/g and the heat of fusion is 24
galben [10]

The mass of iron block is 500 g. The amount of energy required to melt the iron block needs to be calculated. Melting means conversion of solid to liquid thus, heat of fusion is used which is 247 J/g.

From heat of fusion, 247 J of energy is released by melting 1 g of iron block. Thus, the amount of heat released by melting 500 g of iron rod will be:

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3 0
2 years ago
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127) Thirty-six colonies grew in nutrient agar from 1.0 ml of undiluted sample in a standard plate count. How many cells were in
SIZIF [17.4K]

Answer:

36

Explanation:

Since the sample was undiluted the number of colonies is the number that grew on the nutrient agar which is 36 colonies. If it was diluted for example let say 0.1 ml from a dilution in which 1 ml of the sample was added to 9 ml of water, and it grew  colonies then  0.1 ml  yielded  6 colonies, 1 ml of the diluted sample will yield 60 colonies and 10 ml will have 600 colonies and therefore the 1 ml undiluted sample will have 600 colonies.

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A person is pushing a box across a table. The measured forces on the box are 10N, 14N, 7N, 10N. Which force is represented by 7N
Vlad1618 [11]
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Justification:

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So, the normal force and weight (along with any other vertical component of a force applied on the box) must be 10 N and 10 N.

The other two forces: 14 N and 7 N are the forces in the plane of the table and should be opposite in a same line. The 14 N force is the responsible of the motion and the 7N force is opposing the 14 N force, so the 7N force has to be the friction force. Of course, 14N - 7N > 0 which is why the box is moving.
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