Formula of hydrated sodium carbonate : Na₂CO₃.10H₂O, so moles of water in one mole of hydrated salt = 10
<h3>Further explanation</h3>
Hydrate is a compound that binds water (H₂O), usually in the form of crystals/ solids
If these compounds are dissolved in water or heated, the hydrates can decompose:
Example: X.YH₂O (s) → X (aq) + YH₂O (l)
The formula for the hydrated compound contains: YH2O
The mole ratio shows the ratio of the coefficients of the hydrate compound
10.45 hydrated sodium carbonate(Na₂CO₃.xH₂O) were heated until 3.87 of 3.87of anhydrous (Na₂CO₃) remained, so
mass H₂O released :
mass Na₂CO₃ = 3.87 g
mol ratio Na₂CO₃(MW= g/mol) : H₂O(MW=18 g/mol) =
Answer:
Explanation:
Hello,
In this case, considering that the by-mass percent of water is:
Given such percent and the mass of the sample, we can find the mass of water in grams in the sample by solving for it as shown below:
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Answer:
n NaHCO3 = 9.6 E-3 mol
Explanation:
balanced reaction:
- 2 NaHCO3(s) + H2SO4(ac) ↔ Na2SO4(ac) + 2 CO2(g) + 2 H2O(l)
- assuming a concentration of H2SO4 6M....normally worked in the lab
⇒ n H2SO4 = 8 E-4 L * 6 mol/L = 4.8 E-3 mol H2SO4
according to balanced reaction, we have that for every mol of H2SO4 there are two mol of NaHCO3 ( sodium bicarbonate)
⇒ mol NaHCO3 = 4.8 E-3 mol H2SO4 * ( 2 mol NaHCO3 / mol H2SO4 )
⇒ ,mol NaHCO3 = 9.6 E-3 mol
So 9.6 E-3 mol NaHCO3, are the minimun moles necessary to neutralize the acid.
Answer:
The statement that describes the gas of neon is
1. They are far apart.
2. They move constantly.
3. They move freely in all directions.
4. They move at high speed. Neon is termed as a chemical element. It is a noble gas.
It is odorless, colorless, inert monatomic gas when under standard condition. Neon is the second of the rare gases to be discovered. The second lightest inert gas.
Explanation:i just know oki
Answer: 238.6 J
Explanation:
According to the law of conservation of energy, energy can neither be created nor be destroyed. It can only be transformed from one form to another.
Endothermic reactions are those in which heat is absorbed by the system and thus the energy of products is higher than the energy of reactants.
For the given reaction:
Energy of A = 85.1 J
Energy of B = 87.9 J
Energy on reactant side = Energy of A + Energy of B + Energy absorbed 85.1 + 87.9 + 104.3 = 277.3 J
Energy on reactant side = Energy on product side = 277.3 J
Energy on product side = Energy of C + Energy of D
277.3 J = 38.7 J + Energy of D
Energy of D = 238.6 J
Thus chemical energy product D must contain is 238.6 J
