About 1350 W/m2 of electromagnetic energy reaches the upper atmosphere of the earth from the sun, which is 1.5 × 1011 m away. Us
1 answer:
To solve the problem it is necessary to address the concepts of power and intensity of a wave. The intensity of one is uniformly distributed over a distance, is proportional to power and inversely proportional to the square of the distance from the source.
Theoretically it is expressed as
Re-arrange for P,
Replacing with our values we have
Therefore the average power output of the sun is
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Answer:
f3 = 102 Hz
Explanation:
To find the frequency of the sound produced by the pipe you use the following formula:
n: number of the harmonic = 3
vs: speed of sound = 340 m/s
L: length of the pipe = 2.5 m
You replace the values of n, L and vs in order to calculate the frequency:
hence, the frequency of the third overtone is 102 Hz
Answer:
B_o = 1.013μT
Explanation:
To find B_o you take into account the formula for the emf:
where you used that A (area of the loop) is constant, an also the angle between the direction of B and the normal to A.
By applying the derivative you obtain:
when the emf is maximum the angle between B and the normal to A is zero, that is, cosθ = 1 or -1. Furthermore the cos function is 1 or -1. Hence:
hence, B_o = 1.013μT