Answer:

Explanation:
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In this case, since no information about the reacting hydrogen is given, we can assume that it completely react with the 28.0 g of acetylene to yield ethane. In such a way, via the 1:1 mole ratio between acetylene (molar mass = 26 g/mol) and ethane (molar mass = 30 g/mol), we compute the yielded grams, or the theoretical yield of ethane as shown below:

Hence, by knowing that the percent yield is computed via the actual yield (24.5 g) over the theoretical yield, we obtain:

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Answer:
ΔU=-369.2 kJ/mol.
Explanation:
We start from the equation:
Δ(H)=ΔU+Δ(PV), which is an extension of the well known relation: H=U+PV.
If Δ(PV) were calculated by ideal gas law,
PV=nRT
Δ(PV)=RTΔn.
Where Δn is the change of moles due to the reaction; but, this reaction does not give a moles change (Four moles of HCl produced from 4 moles of reactants), so Δ(PV)=0.
So, for this case, ΔH=ΔU.
The enthalpy of reaction given is for one mole of reactant, so the enthalpy of reaction for the reaction of interest must be multiplied by two:

ΔU=-369.2 kJ/mol.
Answer: The are bodies of rock or gas that are named for ancient gods.
Explanation:
Earth is the THIRD planet in the solar system. It support life of all living organisms.
VENUS is the second planet in our solar system. It is named after the Roman goddess of love and beauty.
MARS is the fourth planet in our solar system. It is named after the Roman goddess of war.
Thus, Venus and Mars, are EARTH NEIGHBORS
<h3>Answer:</h3>
Mass = 96.47 g
<h3>
Solution:</h3>
Data Given:
M.Mass = 28.97 g.mol⁻¹
Moles = 3.33 mol
Mass = ??
Formula Used:
Moles = Mass ÷ M.Mass
Solving for Mass,
Mass = Moles × M.Mass
Putting values,
Mass = 3.33 mol × 28.97 g.mol⁻¹
Mass = 96.4701 g
Rounding to four significant numbers,
Mass = 96.47 g
Answer:
Al (s) + AgClO3 (aq) will result in a chemical reaction.
Al(s) + 3AgClO₃(aq) -----> Al(ClO₃)₃(aq) + 3Ag(s)
Cd(s) + CuNO3(aq) will also result in a chemical reaction.
Cd(s) + 2CuNO₃ -----> Cd(NO₃)₂ + 2Cu
Explanation:
For chemical reactions, metals lower on the activity series cannot normally displace ions of metals higher than them in the activity series.
Metals at the lower end of the activity series are not easily oxidized.
The activity series is attached to this solution. (Note: Cadmium is not on the attached chart, but Cadmium is between Iron (Fe) & Cobalt (Co) on the activity series)
- Pb is way lower Mg in the activity series, hence, it cannot become oxidized by displacing Mg2+ ion in solution.
- Al is way higher than Ag in the activity series. Hence it will easily be oxidized and displace displace Ag from it's solution easily.
- Cadmium will displace Copper in solution too because Cd is higher than Cu on the activity series.
- Platinum cannot displace Cobalt from solution as Pt is lower than Co on the activity series.