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makvit [3.9K]
1 year ago
13

A TV satellite broadcasts at a frequency of 5000 MHz, (1 MHz = 1 million Hertz). What is the wavelength of this radiation?

Physics
2 answers:
Nitella [24]1 year ago
5 0

Answer:

\lambda=0.06\ m

Explanation:

Given:

  • frequency of the broadcast, f=5000\ MHz=5\times 10^9\ Hz
  • we have the speed of the radiation equal to the speed of light, c=3\times 10^8\ m.s^{-1}

The broadcast waves are the electromagnetic waves but it can travel only upto a hundred kilometers without any loss of information carried by it.

<u>The relation between the frequency and the wavelength:</u>

\lambda=\frac{c}{f}

\lambda=\frac{3\times 10^8}{5\times 10^9}

\lambda=0.06\ m

goldfiish [28.3K]1 year ago
5 0

Answer:

The wavelength of this radiation is 0.06 m.

Explanation:

Given that,

Frequency = 5000 MHz

We know that,

Speed of light c= 3\times10^{8}\ m/s

We need to calculate the wavelength of this radiation

Using formula of wavelength

\lambda=\dfrac{c}{\nu}

Where, \lambda = wavelength

\nu = frequency

c = speed of light

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{5\times10^{9}}

\lambda=0.06\ m

Hence, The wavelength of this radiation is 0.06 m.

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anyanavicka [17]

Answer:

a) P = 15993.6 N/m²

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Explanation:

Given:

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substituting the value in the formula for pressure,

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P = 13.6 × 10³ × 9.8 × 0.12

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substituting the value in the formula for pressure,

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P' = 13.6 × 10³ × 9.8 × 0.083

or

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2 years ago
Charina says that when waves interact with an object, they will interfere with the object, and that when waves interact with oth
s344n2d4d5 [400]
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1 year ago
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frez [133]
 (u) = 20 m/s 
(v) = 0 m/s 
<span> (t) = 4 s 
</span>
<span>0 = 20 + a(4) 

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8 0
2 years ago
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An organ pipe is tuned to exactly 384 Hz when the temperature in the room is 20°C. Later, when the air has warmed up to 25°C, th
maksim [4K]

Answer: A. Greater than 384 Hz

Explanation:

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Now, we are given that temperature has risen from 20°C to 25°C meaning it has increases. So it implies that velocity must also increase.

Also, the velocity for organ pipe is directly proportional to its frequency. Now if velocity increases frequency must also increase. In this case, the original frequency is 384 Hz. Now increasing the temperature resulted in increase in velocity and thus increase in frequency.

So option a is correct. i.e. now frequency will be greater than 384 Hz.

3 0
2 years ago
Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2ax. The problem requires so
lisabon 2012 [21]

As per kinematics equation we are given that

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now we are given that

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from above equation we have

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0 = 475.24 + 5.1 x

x = 93.2 m

so it will cover a distance of 93.2 m

7 0
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