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2 years ago

A TV satellite broadcasts at a frequency of 5000 MHz, (1 MHz = 1 million Hertz). What is the wavelength of this radiation?

Physics

2 answers:

Nitella [24]2 years ago

5 0

Answer:

$\lambda=0.06\ m$

Explanation:

Given:

frequency of the broadcast, $f=5000\ MHz=5\times 10^9\ Hz$

we have the speed of the radiation equal to the speed of light, $c=3\times 10^8\ m.s^{-1}$

The broadcast waves are the electromagnetic waves but it can travel only upto a hundred kilometers without any loss of information carried by it.

The relation between the frequency and the wavelength:

$\lambda=\frac{c}{f}$

$\lambda=\frac{3\times 10^8}{5\times 10^9}$

$\lambda=0.06\ m$

goldfiish [28.3K]2 years ago

5 0

Answer:

The wavelength of this radiation is 0.06 m.

Explanation:

Given that,

Frequency = 5000 MHz

We know that,

Speed of light $c= 3\times10^{8}\ m/s$

We need to calculate the wavelength of this radiation

Using formula of wavelength

$\lambda=\dfrac{c}{\nu}$

Where, $\lambda$ = wavelength

$\nu$ = frequency

c = speed of light

Put the value into the formula

$\lambda=\dfrac{3\times10^{8}}{5\times10^{9}}$

$\lambda=0.06\ m$

Hence, The wavelength of this radiation is 0.06 m.

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A baseball player exerts a force of 100 N on a ball for a distance of 0.5 mas he throws it. If the ball has a mass of 0.15 kg, w

Aloiza [94]

Answer:

25.82 m/s

Explanation:

We are given;

Force exerted by baseball player; F = 100 N

Distance covered by ball; d = 0.5 m

Mass of ball; m = 0.15 kg

Now, to get the velocity at which the ball leaves his hand, we will equate the work done to the kinetic energy.

We should note that work done is a measure of the energy exerted by the baseball player.

Thus;

F × d = ½mv²

100 × 0.5 = ½ × 0.15 × v²

v² = (2 × 100 × 0.5)/0.15

v² = 666.67

v = √666.67

v = 25.82 m/s

4 0

1 year ago

A wire of 1mm diameter and 1m long fixed at one end is stretched by 0.01mm when a lend of 10 kg is attached to its free end.calc

Otrada [13]

Answer:

E = 1.25×10¹³ N/m²

Explanation:

Young's modulus is defined as:

E = stress / strain

E = (F / A) / (dL / L)

E = (F L) / (A dL)

Given:

F = 10 kg × 9.8 m/s² = 98 N

L = 1 m

dL = 10⁻⁵ m

A = π/4 (0.001 m)² = 7.85×10⁻⁷ m²

Solve:

E = (98 N × 1 m) / (7.85×10⁻⁷ m² × 10⁻⁵ m)

E = 1.25×10¹³ N/m²

Round as needed.

5 0

2 years ago

What is the y component of a vector defined as 12.2m at 81.5°?

sergejj [24]

Answer:

Explanation:

This is a displacement vector since it is defined in terms of distance (meters, to be exact). The way you find the y-component is

$V_y=Vsin\theta$ which says that you multiply the magnitude of the vector (its length) by the sin of the direction (the angle):

$V_y=12.2sin(81.5)$ and get

$V_y=$ 12.1 m

3 0

2 years ago

Serena is a research student who has conducted an experiment on the discoloration of marble. Read about Serena’s experiment. The

sergij07 [2.7K]

The two flaws in her experiment’s design are

- She introduced at least one confounding variable. - She tried to test multiple hypotheses at a time

In the above mentioned experiment she had to have four samples to prove four hypotheses, each one separately and not to mix two hypotheses in an alone sample, that what it brings as consequence is the confusion.

3 0

2 years ago

The standing vertical jump is a good test of an athlete's strength and fitness. The athlete goes into a deep crouch, then extend

SashulF [63]

Answer:

The athlete will rise 1.10 meters off the ground

Explanation:

Vertical Motion

If an object is launched vertically upwards at an initial speed vo, then it will reach a maximum height given by

$\displaystyle y_m=\frac{v_o^2}{2g}$

The athlete can exert a net force upwards equal to twice his weight. It makes him accelerate upwards at

$\displaystyle a=\frac{F_n}{m}=\frac{2W}{m}=2g$

The speed at the end of his push can be computed by

$v^2=2ay$

Replacing the value of a obtained above:

$v^2=4gy$

where y is the length of this crouch

$v^2=4\cdot 9.8\cdot 0.55$

$v=4.64\ m/s$

This is the initial speed of this vertical launch, thus

$\displaystyle y_m=\frac{4.64^2}{2\cdot 9.8}$

$y_m=1.10\ m$

5 0

2 years ago