answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lorico [155]
2 years ago
3

Metals are used in many products because of the characteristic properties that most metals share. Which properties of the metal

tungsten make it useful in the thin, glowing filaments of light bulbs? A. Tungsten is electrically conductive, ductile, and opaque. B.Tungsten is ductile, is malleable, and has a high luster. C.Tungsten is ductile, has a high melting point, and is electrically conductive. D.Tungsten has a high luster, has a high melting point, and is silver in color.
Chemistry
1 answer:
svp [43]2 years ago
3 0

Answer:

Option (c)

Explanation:

The characteristic properties of a metal tungsten are as follows :

  1. It can be cut into hard steel. It means it is ductile.
  2. It is the only metal which has highest melting point i.e. 3410 °C.
  3. It has high temperature mechanical propoerty.
  4. It has luster.

Out of the given options, option (c) gives the best properties of the metal tungsten make it useful in the thin, glowing filaments of light bulbs i.e. ".Tungsten is ductile, has a high melting point, and is electrically conductive"

You might be interested in
Titanium metal requires a photon with a minimum energy of 6.94×10⁻¹⁹J to emit electrons. What is the wavelength of this light? E
Elena-2011 [213]

Answer:2.86x10^-7m

Explanation:E=hc/^

E=6.94x10^-19J

c = 2.9979x10^8m/s

h= 6.626x10^-34Js

^ =( 6.626x10^-34)x( 2.9979x 10^8)/ 6.94x10^-19

= 2.86x10^-7m

5 0
2 years ago
create a flowchart that outlines when to use dimensional analysis and when to use scientific notation.
murzikaleks [220]

Answer:

  see attached

Explanation:

Dimensional analysis is useful whenever dimensions are involved. Unless it is quite clear that all of the problem dimensions are consistent (for example, all speeds in miles per hour, or all angles in degrees), dimensional analysis can be useful for keeping the math straight.

Only units of the same dimensions can be added or subtracted. When numbers are multiplied or divided or raised to a power, dimensional analysis can help ensure that the appropriate operations are being used on appropriate numbers. It can also help ensure that dimensions are being combined properly to give appropriate derived dimensions.

__

Scientific notation is a way of writing very large or very small numbers compactly. It can also help with "order of magnitude" estimates. If an answer using SI prefixes is appropriate, or if a number can be conveniently expressed in standard form, then scientific notation is usually not required.

On the other hand, SI prefixes may not be appropriate in some cases, or a problem may specify that scientific notation be used for expressing results. In those instances, scientific notation should be used.

7 0
2 years ago
What pressure (in atm) would be exerted by 76 g of fluorine gas (f2) in a 1.50 liter vessel at -37oc? (a) 26 atm(b) 4.1 atm(c) 1
nirvana33 [79]

<span>Let's assume that the F</span>₂ gas has ideal gas behavior. 

<span> Then we can use ideal gas formula,
PV = nRT

Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol</span>⁻¹ K⁻<span>¹) and T is temperature in Kelvin.</span>


Moles = mass / molar mass


Molar mass of F₂ = 38 g/mol

Mass of F₂  = 76 g

Hence, moles of F₂ = 76 g / 38 g/mol = 2 mol

<span>
P = ?
V = 1.5 L = 1.5 x 10</span>⁻³ m³

n = 2 mol

R = 8.314 J mol⁻¹ K⁻<span>¹
T = -37 °C = 236 K

By substitution,
</span>

P x 1.5 x 10⁻³ m³ = 2 mol x 8.314 J mol⁻¹ K⁻¹ x 236 K

                         p = 2616138.67 Pa

                         p = 25.8 atm = 26 atm


Hence, the pressure of the gas is 26 atm.

Answer is "a".

<span>

</span>
5 0
2 years ago
Which of the following statements best describes the Aufbau principle?
dsp73
The answer is the choice A
7 0
2 years ago
In Part A, you found the amount of product (1.80 mol P2O5 ) formed from the given amount of phosphorus and excess oxygen. In Par
Finger [1]

First step is to balance the reaction equation. Hence we get P4 + 5 O2 => 2 P2O5

Second, we calculate the amounts we start with

P4: 112 g = 112 g/ 124 g/mol – 0.903 mol

O2: 112 g = 112 g / 32 g/mol = 3.5 mol

Lastly, we calculate the amount of P2O5 produced.

2.5 mol of O2 will react with 0.7 mol of P2O5 to produce 1.4 mol of P2O5.

This is 1.4 * (31*2 + 16*5) = 198.8 g

3 0
2 years ago
Other questions:
  • 6. A rectangular block of wood has length 6.0 cm, width 5.0 cm and height 10.0 cm. It has mass l50g. What is the mass of a block
    7·1 answer
  • If 2.0 ml of 6.0m hcl is used to make a 500.0-ml aqueous solution, what is the molarity of the dilute solution?
    10·2 answers
  • 25 g of ethyl alcohol is dissolved in 100 ml of water (density = 0.99993 at 20 oc). what is the % w/w for the ethyl alcohol in t
    11·1 answer
  • Using the equation, C5H12 + 8O2 Imported Asset 5CO2 + 6H2O, if an excess of pentane (C5H12) were supplied, but only 4 moles of o
    9·2 answers
  • What is the ph of a solution of 0.400 m k2hpo4, potassium hydrogen phosphate?
    5·1 answer
  • A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200
    7·1 answer
  • - Equilibrium shifts for slightly soluble compounds The reaction for the formation of a saturated solution of silver bromide (Ag
    9·1 answer
  • A silver sphere has a mass of 5.492 g and a diameter of 10.0 mm. What is the density of silver metal in grams per cubic centimet
    7·1 answer
  • The shape of hair is determined in part by the pattern of disulfide bonds in keratin, its major protein. From first to last, arr
    6·1 answer
  • Activity 7: Crossword Puzzle
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!