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DIA [1.3K]
2 years ago
14

50g nitrous oxide combines with 50g oxygen form dinitrogen tetroxide according to the balanced equation below.

Chemistry
1 answer:
photoshop1234 [79]2 years ago
7 0

Limiting reactant : O₂

Mass of  N₂O₄ produced = 95.83 g

<h3>Further explanation</h3>

Given

50g nitrous oxide

50g oxygen

Reaction

2N20 + 302 - 2N204

Required

Limiting reactant

mass of N204 produced

Solution

mol N₂O :

\tt =\dfrac{50}{44}=1.136

mol O₂ :

\tt =\dfrac{50}{32}=1.5625

2N₂O+3O₂⇒ 2N₂O₄

ICE method

1.136    1.5625

1.0416  1.5625    1.0416

0.0944    0          1.0416

Limiting reactant : Oxygen-O₂

Mass N₂O₄(MW=92 g/mol) :

\tt =mol\times MW=1.0416\times 92=95.83~g

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amid [387]
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7 0
2 years ago
How many liters of oxygen gas can be produced at stp from the decomposition of 0.250 l of 3.00 m h2o2 in the reaction according
Wewaii [24]

the balanced chemical equation for the decomposition of H₂O₂ is as follows

2H₂O₂ ---> 2H₂O + O₂

stoichiometry of H₂O₂ to O₂ is 2:1

the number of moles of H₂O₂ decomposed is - 0.250 L x 3.00 mol/L = 0.75 mol

according to stoichiometry the number of O₂ moles is half the number of H₂O₂ moles decomposed

number of moles of O₂ - 0.75 mol / 2 = 0.375 mol

apply the ideal gas law equation to find the volume

PV = nRT

where P - standard pressure - 10⁵ Pa

V - volume

n - number of moles 0.375 mol

R - universal gas constant - 8.314 Jmol⁻¹K⁻¹

T - standard temperature - 273 K

substituting the values in the equation

10⁵ Pa x V = 0.375 mol x 8.314 Jmol⁻¹K⁻¹ x 273 K

V = 8.5 L

volume of O₂ gas is 8.5 L

6 0
2 years ago
How many moles of BCl3 are needed to produce 10.0 g of HCl(aq) in the following reaction? (HCl molar mass is 36.46 g/mol).
Scilla [17]

Answer:

Moles of BCl₃ needed = 0.089 mol

Explanation:

Given data:

Moles of BCl₃ needed = ?

Mass of HCl produced = 10.0 g

Solution:

Chemical equation:

BCl₃ + 3H₂O  →     3HCl + B(OH)₃

Number of moles of HCl:

Number of moles = mass/molar mass

Number of moles = 10.0 g/ 36.46 g/mol

Number of moles = 0.27 mol

Now we will compare the moles of HCl with BCl₃.

               HCl             :           BCl₃

                 3               :             1

             0.27             :            1/3×0.27 = 0.089 mol

6 0
2 years ago
Describe the process used to measure out a specific mass of a solid
Svetlanka [38]
Although the process varies slightly from one material to another, the general process is as follows:

1) Choose an appropriate container for the solid. This may be a petri dish or a beaker in which you want to prepare the solution of the solid or any other lab equipment.

2) Place the container on a mass balance, then turn the balance on. The mass balance will automatically zero-out the mass of the container, so that any mass that you add on the container will be the mass of the solid. Alternatively, you may first measure the mass of the empty container alone.

3) Add the solid using a lab spatula. The solid should be added more slowly when the reading on the scale comes close to the desired value.

4) Remove the container from the mass balance after the desired amount of solid has been added.
7 0
2 years ago
What is the name of the functional group that is attached to this hydrocarbon? The first and last of a chain of three carbons ar
disa [49]

Answer:

Ketone

Explanation:

As you are stating here, we have a carbonated chain of three carbons, and the first and last has 3 Hydrogens, then this means that we have CH₃ . The center carbon is a carbon double bonded to oxygen.

In general terms this belongs to the carbonyl group. However, this alone does not represent a functional group, but when it's in a chain with other radycals or chains, it becomes a functional group.

In this case, the molecule you are talking here is the following:

CH₃ - CO - CH₃

This molecule is known as the Acetone, and has the general form of:

R - CO - R'

Which belongs to a ketone as a functional group.

4 0
2 years ago
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