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Bond [772]
2 years ago
3

The equation represents the combustion of sucrose. C12H22O11 + 12O2 Right arrow. 12CO2 + 11H2O If there are 10.0 g of sucrose an

d 8.0 g of oxygen, how many moles of sucrose are available for this reaction? 0.029 mol 0.250 mol 0.351 mol 3.00 mol
Chemistry
1 answer:
svp [43]2 years ago
7 0

Answer: 0.029 mol

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

The balanced chemical equation is:

C_{12}H_{22}O_{11}+12O_2\rightarrow 12CO_2+11H_2O

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=\frac{10.0g}{342g/mol}}=0.029moles

Thus there are 0.029 moles of sucrose

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D. Producers im sure of it hope im right

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2 years ago
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Micky Mo is a 64-year-old male admitted to the emergency room for asthma. His laboratory results are as follows: pH 7.31, pCO2 h
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Answer:

Micky Mo is suffering from respiratory acidosis.

Explanation:

The pCO2 level in micky"s body is higher than normal it means the excess amount of  CO2 will reacts with water to generate carbonic acid(H2CO3).

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2 years ago
6) A 0.20 ml CO2 bubble in a cake batter is at 27°C. In the oven it gets
Nata [24]

Answer: The new volume of cake is 1.31 mL.

Explanation:

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Formula used to calculate new volume is as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{0.20 mL}{27^{o}C} = \frac{V_{2}}{177^{o}C}\\V_{2} = 1.31 mL

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5 0
2 years ago
identify the element in period 3 that requires the least amount of energy to remove the most loosely held electrons from a mole
OLga [1]

Answer:

The element is Na

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Ionization energy is the energy needed to release the last electron from an atom in its ground state to the gaseous state.  It is a periodic property that increases as we go through the periods of the periodic table, but decreases if we move in groups.  Sodium has thr ionic radius (another periodic property) that is too large, making it easier to release the electron away, since it is too far from the nucleus.

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2 years ago
The potential energy of a catapult was completely converted into kinetic energy by releasing a small stone with a mass of 20 gra
vladimir1956 [14]

1,000 grams = 1 kilogram

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                          (1/2) (0.02) x (15)² =


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2 years ago
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