The long pendulum shown is drawn aside until the ball has risen 0.5 m. it is then given an initial speed of 3.0 m/s.. the speed
1 answer:
m = mass of the ball being raised
h = height to which the ball is raised = 0.5 m
v₀ = initial speed given to the ball = 3
v = final speed of the ball at its lowest position = ?
using conservation of energy
final kinetic energy at the lowest point = initial kinetic energy + initial potential energy
(0.5) m v² = (0.5) m v₀² + mgh
dividing each term by "m"
(0.5) v² = (0.5) v₀² + gh
inserting the values
(0.5) v² = (0.5) (3)² + (9.8) (0.5)
v = 4.34 m/s
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Answer:
Explanation:
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Now, the horizontal and vertical components of these forces are:
As the system is in equilibrium, the net force in x and y directions is 0 and net torque about any point is also 0. Therefore,
Now, let us find the net torque about a point 'P' that is just above the center of mass at the upper edge of the bar.
At point 'P', there are no torques exerted by the F₁x and F₂x nor the weight of the bar as they all lie along the axis of rotation.
Therefore, the net torque by the forces will be zero. This gives,
But,
Therefore,
We know,
∴
Answer:
Explanation:
The electric flux through the rectangle is given by
where
E is the electric field strength
A is the area of the rectange
is the angle between the direction of the electric field and of the vector normal to the plane of the rectangle
In this problem we have
E = 125 000 N/C
The area of the rectangle is
and the angle is
so, the electric flux is